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In a certain city, the ratio of the number of people who

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Director
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In a certain city, the ratio of the number of people who [#permalink] New post 17 Oct 2006, 07:37
00:00
A
B
C
D
E

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In a certain city, the ratio of the number of people who purchase newspaper X to the number of people who purchase newspaper Y is 7:1. What percent of the population purchases newspaper Y?

I . Twenty-seven percent of the population purchases neither newspaper X nor newspaper Y.
II. Seventy percent of the people who purchase newspaper Y also purchase newspaper X.
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Re: DS: Newspapers X and Y [#permalink] New post 17 Oct 2006, 10:25
anandsebastin wrote:
In a certain city, the ratio of the number of people who purchase newspaper X to the number of people who purchase newspaper Y is 7:1. What percent of the population purchases newspaper Y?

I . Twenty-seven percent of the population purchases neither newspaper X nor newspaper Y.
II. Seventy percent of the people who purchase newspaper Y also purchase newspaper X.


Tough one. Statement 1 &2 on their own are not sufficient as both provide vital information. So that knocks out A, B & D. C & E remain. My vote is with E. 27% do not read any paper at all. So that leaves 73% of the population who read 1) only X 2) Only Y or 3) both X& Y.

I think I fell for somesort of trap here though:cry:
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 [#permalink] New post 17 Oct 2006, 11:29
Very Tricky...
st1 says 23% do not purchase x or y..but we cannot assume that remaining 67 purcahse x y or both..there other brands avaliable.. insuff
st2 says 70% who purchase y also purchase x this tells us that both xy=70/100 y...inuff as no information abt x...

Total =x+y-both+neither

Neither =23/100 T=0.23T ..from st 1
From st2 both xy =0.7y x=7y
Thus combining
T=7y+y-0.7y+.23T
We solve to get Y/T then multiply by 100 to get the required percentage..
Hence answer should be C..

Had chosen E earlier..

Last edited by yogeshsheth on 17 Oct 2006, 21:23, edited 1 time in total.
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 [#permalink] New post 17 Oct 2006, 12:53
A may be?

I) 100 - 27 = 83 percent buy newspapers( either X or Y).
X:Y = 7:1
X = (7/8) * 83
Y = (1/8) * 83

A.
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 [#permalink] New post 17 Oct 2006, 20:36
Code:
In a certain city, the ratio of the number of people who purchase newspaper X to the number of people who purchase newspaper Y is 7:1. What percent of the population purchases newspaper Y?


I think the ANS depends on how you understand the Question.

CASE 1 : IGNORE OVERLAP
Here , only the % of people who purchase News Paper Y is asked.
Assuming that we can ignore the overlap (people purchasing both X n Y),
and find only the Y %

A is SUFF.
We have - 73 % of people who read atleast 1 news paper, be it X, be it Y or be it both.
We are given the ratio of X to Y. Y % can be found out.

CASE 1 : OVERLAP CONSIDERED

Here , its E I ges.

correct me if I am wrong.
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 [#permalink] New post 17 Oct 2006, 20:56
The answer is C.

Total = X+Y - both + neither

Need to find y/Total

From stmt1: Neither = 0 Insuff

From stmt2: Both= 0.75*y Insuff

Combined

y/Total = y/(y*7 +y - 0.75*y)

y can be cancelled out . Sufficient.
  [#permalink] 17 Oct 2006, 20:56
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