Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 29 Jun 2016, 00:16

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In a certain class 1/3 of students are honors 1/4 of

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 19 Jun 2003
Posts: 151
Followers: 1

Kudos [?]: 23 [0], given: 0

In a certain class 1/3 of students are honors 1/4 of [#permalink]

### Show Tags

24 Aug 2004, 21:22
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In a certain class 1/3 of students are honors 1/4 of students play varisity sports. If 12 students are honors and play varisty sports , what is the least number of students in class?

20

22

36

48

144

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5062
Location: Singapore
Followers: 29

Kudos [?]: 282 [0], given: 0

### Show Tags

24 Aug 2004, 22:34
Backsolve.
Using 36, 1/3(36)=12
1/4(36)=9
Impossible, since 12 are both.

Using 48, 1/3(48) = 16
1/4(48) = 12

Possible, since we have 12 playing sports now. We are asked for least possible number, so this has to be the one, since 144 will satisfy the condition given but have an excess of students who are only playing one role.
Senior Manager
Joined: 22 Jun 2004
Posts: 393
Location: Bangalore, India
Followers: 1

Kudos [?]: 5 [0], given: 0

Re: PS: varisty sports [#permalink]

### Show Tags

25 Aug 2004, 04:13
The least number comes when both the categories have the highest overlap. Thus, the maximum overlap is all the students that play varsity sports are honors. => x/4 = 12. i.e., x = 48 which is the minimum.

afife76 wrote:
In a certain class 1/3 of students are honors 1/4 of students play varisity sports. If 12 students are honors and play varisty sports , what is the least number of students in class?

20

22

36

48

144

_________________

Awaiting response,

Thnx & Rgds,
Chandra

Intern
Joined: 10 Aug 2004
Posts: 40
Followers: 0

Kudos [?]: 1 [0], given: 0

### Show Tags

25 Aug 2004, 08:34
My answer is 144

Total=Group1+group2-both+neither
144=48+36-12+60
144=144.
Intern
Joined: 10 Aug 2004
Posts: 40
Followers: 0

Kudos [?]: 1 [0], given: 0

### Show Tags

25 Aug 2004, 08:35
My answer is 144

Total=Group1+group2-both+neither
144=48+36-12+60
144=144.
Intern
Joined: 10 Aug 2004
Posts: 40
Followers: 0

Kudos [?]: 1 [0], given: 0

### Show Tags

25 Aug 2004, 08:37
I got the math wrong, please ignore last post.
Manager
Joined: 19 Jun 2003
Posts: 151
Followers: 1

Kudos [?]: 23 [0], given: 0

Re: PS: varisty sports [#permalink]

### Show Tags

25 Aug 2004, 12:14
mallelac wrote:
The least number comes when both the categories have the highest overlap. Thus, the maximum overlap is all the students that play varsity sports are honors. => x/4 = 12. i.e., x = 48 which is the minimum.

Mallelac, your approach is very cool!!

Thank you to both!!
Re: PS: varisty sports   [#permalink] 25 Aug 2004, 12:14
Display posts from previous: Sort by

# In a certain class 1/3 of students are honors 1/4 of

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.