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In a certain company, if 75% of the employees usually use a

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In a certain company, if 75% of the employees usually use a [#permalink] New post 10 Feb 2011, 15:59
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In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?

(1) 60% of the employees who usually use a laptop also use a PDA.
(2) 90% of the employees who usually use a PDA also use a laptop.
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Re: In a certain company, if 75% of the employees usually u [#permalink] New post 10 Feb 2011, 16:50
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banksy wrote:
In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?
(1) 60% of the employees who usually use a laptop also use a PDA.
(2) 90% of the employees who usually use a PDA also use a laptop.


In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?

Assume there are total of 100 employees. Given: {Laptop users}=75. Question: {PDA users}=?

(1) 60% of the employees who usually use a laptop also use a PDA --> 0.6*{Laptop users}={Those who use both} --> {Both}=0.6*75=45. Not sufficient.

(2) 90% of the employees who usually use a PDA also use a laptop --> again {Both}=0.9*{PDA users}. Not sufficient.

(1)+(2) {Both}=45=0.9*{PDA users} --> {PDA users}=45/0.9=50. Sufficient.

Answer: C.
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Re: In a certain company, if 75% of the employees usually u [#permalink] New post 11 Feb 2011, 00:09
banksy wrote:
In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?
(1) 60% of the employees who usually use a laptop also use a PDA.
(2) 90% of the employees who usually use a PDA also use a laptop.

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Re: In a certain company, if 75% of the employees usually u [#permalink] New post 19 Apr 2011, 20:38
(1)

0.6 L Have PDA

So 0.6 * 75 Have both = 45 Have both

Not Sufficient, we don't know P


(2)

0.9P have laptop

Not Sufficient, we don't know P

(1) and (2)

0.9P = 45

=> P = 50

Answer - C
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Re: In a certain company, if 75% of the employees usually u [#permalink] New post 22 Apr 2011, 18:02
1. Not sufficient .

here we have laptop only , laptop & pda . still not enough to find out pda .

2. Not sufficient.


we know that 90 % of pda user also use laptop . not enough to find out pda.

together we have

45E/100 = (90/100) PDA. enough to find pda interms of employees.

Answer is C.
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Re: In a certain company, if 75% of the employees usually use a [#permalink] New post 14 Jun 2013, 22:16
I know this thread has been inactive for a while but if anybody could help solve my query it would be great.

See if you are assuming that 100 employees are there then
75% use laptops so 75 employees
1) 60%(75) use both so 45 employees
so by using the principle of sets 100= 75 + P -45
hence P=70
2)100=75 + P - (90/100)*P
solve this also and you'll get P
So the correct answer should be 'D' right?
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Re: In a certain company, if 75% of the employees usually use a [#permalink] New post 15 Jun 2013, 00:52
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anishashastri wrote:
I know this thread has been inactive for a while but if anybody could help solve my query it would be great.

See if you are assuming that 100 employees are there then
75% use laptops so 75 employees
1) 60%(75) use both so 45 employees
so by using the principle of sets 100= 75 + P -45
hence P=70
2)100=75 + P - (90/100)*P
solve this also and you'll get P
So the correct answer should be 'D' right?


{Total} = {Laptop} + {PDA} - {Both} + {Neither}. So, you'll have one more variable in each statement thus you won't be able to solve.

Next, if you solve 100=75+P-0.9*P you'll get P=250, which does not make sense.

And finally, on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other but from 100=75+P-45 you get P=70 while from 100=75+P-0.9*P you get P=250, which cannot happen on the GMAT.

Hope it's clear.
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Re: In a certain company, if 75% of the employees usually use a [#permalink] New post 15 Jun 2013, 01:38
Bunuel wrote:
anishashastri wrote:
I know this thread has been inactive for a while but if anybody could help solve my query it would be great.

See if you are assuming that 100 employees are there then
75% use laptops so 75 employees
1) 60%(75) use both so 45 employees
so by using the principle of sets 100= 75 + P -45
hence P=70
2)100=75 + P - (90/100)*P
solve this also and you'll get P
So the correct answer should be 'D' right?


{Total} = {Laptop} + {PDA} - {Both} + {Neither}. So, you'll have one more variable in each statement thus you won't be able to solve.

Next, if you solve 100=75+P-0.9*P you'll get P=250, which does not make sense.

And finally, on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other but from 100=75+P-45 you get P=70 while from 100=75+P-0.9*P you get P=250, which cannot happen on the GMAT.

Hope it's clear.



Hi,
Appreciate the response. I was under the impression that if nothing has been given about the [Neither] part you can ignore it, anyway thank you! I get it now!
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Re: In a certain company, if 75% of the employees usually u [#permalink] New post 13 Oct 2013, 05:10
Bunuel wrote:
banksy wrote:
In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?
(1) 60% of the employees who usually use a laptop also use a PDA.
(2) 90% of the employees who usually use a PDA also use a laptop.


In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?

Assume there are total of 100 employees. Given: {Laptop users}=75. Question: {PDA users}=?

(1) 60% of the employees who usually use a laptop also use a PDA --> 0.6*{Laptop users}={Those who use both} --> {Both}=0.6*75=45. Not sufficient.

(2) 90% of the employees who usually use a PDA also use a laptop --> again {Both}=0.9*{PDA users}. Not sufficient.

(1)+(2) {Both}=45=0.9*{PDA users} --> {PDA users}=45/0.9=50. Sufficient.

Answer: C.


Hi Bunuel, for OS questions in DS. What is the best practice? I have tried different approaches but always have found drawing one matrix per statement the easiest. Every matrix would contain only the information provided in the question stem and stating clearly what I need to find. In worst case, I would have to draw 3. As a matter of fact, this is often the case. I find it that it can be a bit time consuming and was wondering if you suggest any other approach that could be at least as precise and error-free vs. using this approach
Thanks
Cheers
J
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Re: In a certain company, if 75% of the employees usually u [#permalink] New post 14 Oct 2013, 04:00
Expert's post
jlgdr wrote:
Bunuel wrote:
banksy wrote:
In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?
(1) 60% of the employees who usually use a laptop also use a PDA.
(2) 90% of the employees who usually use a PDA also use a laptop.


In a certain company, if 75% of the employees usually use a laptop, what percent of the employees usually use a PDA (Personal Digital Assistant)?

Assume there are total of 100 employees. Given: {Laptop users}=75. Question: {PDA users}=?

(1) 60% of the employees who usually use a laptop also use a PDA --> 0.6*{Laptop users}={Those who use both} --> {Both}=0.6*75=45. Not sufficient.

(2) 90% of the employees who usually use a PDA also use a laptop --> again {Both}=0.9*{PDA users}. Not sufficient.

(1)+(2) {Both}=45=0.9*{PDA users} --> {PDA users}=45/0.9=50. Sufficient.

Answer: C.


Hi Bunuel, for OS questions in DS. What is the best practice? I have tried different approaches but always have found drawing one matrix per statement the easiest. Every matrix would contain only the information provided in the question stem and stating clearly what I need to find. In worst case, I would have to draw 3. As a matter of fact, this is often the case. I find it that it can be a bit time consuming and was wondering if you suggest any other approach that could be at least as precise and error-free vs. using this approach
Thanks
Cheers
J


There are 3 approaches to tackle 2 overlapping sets problems:
1. Double-set matrix.
2. Venn diagram.
3. Formulas (as in this question).

Which one to choose depends on the problem and your personal preferences.
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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: In a certain company, if 75% of the employees usually u [#permalink] New post 14 Oct 2013, 07:08
There are 3 approaches to tackle 2 overlapping sets problems:
1. Double-set matrix.
2. Venn diagram.
3. Formulas (as in this question).

Which one to choose depends on the problem and your personal preferences.[/quote]

Thank you for pointing that out. I agree that they fit different questions indeed and I have used all of them.
Now strictly for Double-Set matrix problems in DS
Is it the normal practice to draw three matrixes, one for the initial information given, one adding the info on Statement 1
And then a third one only adding info on Statement 2 (which you can then use if 1 and 2 are needed) ?
I find it a bit time consuming but proves to be safer, just wondering if you and other people around here do it this way

Cheers
J :)
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Re: In a certain company, if 75% of the employees usually use a [#permalink] New post 28 May 2014, 23:50
Can anyone help me out with this problem using the double matrix technique. Thanks in Advance
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Re: In a certain company, if 75% of the employees usually use a [#permalink] New post 02 Jun 2014, 01:29
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Re: In a certain company, if 75% of the employees usually use a [#permalink] New post 02 Jun 2014, 04:37
I've written the following message for myself when studying, please ignore it as I realized it was far from well written.

Alright. We've got a few possibilities.

Let's name Laptop L and PDA P, B for both and N for neither.

L P B N = 4 possibilities.

Given is that 75% uses a laptop.

Statement 1: 60% of L also uses P. We've now got our B. 0.75*0.6.

Can we find out the percentage of PDA users from this?

We need B+P to answer that question. So no, we do not have the answer yet. Insufficient.

Statement 2:
90% who uses a PDA also uses a laptop. This tells us that 0.9*x uses a PDA. But we do not know as of now how big the "Both" part is.

But together with statement 1 we get:
0.9*x=0.75*0.6=0.45 x=0.5 So we know now that 50% uses a PDA.

Answer: C

This could probably also have been solved by a probability tree.
Re: In a certain company, if 75% of the employees usually use a   [#permalink] 02 Jun 2014, 04:37
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