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# In a certain department store, which has four sizes of a

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Senior Manager
Joined: 19 Nov 2004
Posts: 284
Location: Germany
Followers: 1

Kudos [?]: 13 [0], given: 0

In a certain department store, which has four sizes of a [#permalink]  30 Dec 2004, 07:24
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In a certain department store, which has four sizes of a specific shirt, there are 1/3 as many small shirts as medium shirts, and 1/2 as many large shirts as small shirts. If there are as many x-large shirts as large shirts, what percent of the shirts in the store are medium?

(A) 10%
(B) 25%
(C) 33%
(D) 50%
(E) 60%
Director
Joined: 14 Oct 2003
Posts: 588
Location: On Vacation at My Crawford, Texas Ranch
Followers: 1

Kudos [?]: 9 [0], given: 0

Re: PS: Number of Shirts [#permalink]  30 Dec 2004, 08:23
maaverick wrote:
In a certain department store, which has four sizes of a specific shirt, there are 1/3 as many small shirts as medium shirts, and 1/2 as many large shirts as small shirts. If there are as many x-large shirts as large shirts, what percent of the shirts in the store are medium?

(A) 10%
(B) 25%
(C) 33%
(D) 50%
(E) 60%

I picked numbers here that satisfied the information given:

Size Number of shirts
S 10
M 30
L 5
X 5
Total 50

thus 30/50 = 60% (E)
Intern
Joined: 07 Aug 2003
Posts: 3
Location: Argentina
Followers: 0

Kudos [?]: 1 [0], given: 0

E 60%

3S=M
2L=L
L=X

M/(S+M+L+X)=1M/(5/3)M=3/5=60%
Director
Joined: 03 Nov 2004
Posts: 868
Followers: 1

Kudos [?]: 19 [0], given: 0

One more for 'E'
1/3M + M + (1/2*1/3M) + (1/2*1/3M) = 100
=>M = 300/5 = 60
Senior Manager
Joined: 19 Nov 2004
Posts: 284
Location: Germany
Followers: 1

Kudos [?]: 13 [0], given: 0

The OA is (E)

Thanks for posting in the explaination.
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