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In a certain district, the ratio of the number of registered [#permalink]
12 Dec 2012, 03:38

2

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00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

65% (03:06) correct
35% (02:06) wrong based on 335 sessions

In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4/5. After these registrations, there were how many more voters in the district registered as Democrats than as Republicans?

Re: In a certain district, the ratio of the number of registered [#permalink]
12 Dec 2012, 03:47

2

This post received KUDOS

Expert's post

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Walkabout wrote:

In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4/5. After these registrations, there were how many more voters in the district registered as Democrats than as Republicans?

(A) 100 (B) 300 (C) 400 (D) 1,000 (E) 2,500

Old ratio: \frac{republicans}{democrats}=\frac{3x}{5x}.

New ratio: \frac{3x+600}{5x+500}=\frac{4}{5} --> x=200.

Current difference is (5x+500)-(3x+600)=2x-100=300.

In a certain district, the ratio of the number of registered [#permalink]
19 Dec 2012, 01:46

In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional R and 500 additional D registered, the ratio was 4/5. After these registrations, the there were how many more voters in the district registered as D than as R?

When you solve the two given equations, you arrive at D = 1000, which is perfectly logical. As R = 3/5 D, R must be 600.

Now comes the thing I don't understand. In the sample solution, the newly registered voters are now added to the above numbers, which results in D = 1000 + 600 = 1500, respectively R = 600 + 600 = 1200. The difference is 300 now, which corresponds to the OA. But isn't it true that the numbers which result from solving the given equations must already be post the additions?

In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional R and 500 additional D registered, the ratio was 4/5. After these registrations, the there were how many more voters in the district registered as D than as R?

When you solve the two given equations, you arrive at D = 1000, which is perfectly logical. As R = 3/5 D, R must be 600.

Now comes the thing I don't understand. In the sample solution, the newly registered voters are now added to the above numbers, which results in D = 1000 + 600 = 1500, respectively R = 600 + 600 = 1200. The difference is 300 now, which corresponds to the OA. But isn't it true that the numbers which result from solving the given equations must already be post the additions?

As for your question: we are asked to find the difference between the numbers of Democrats and Republicans AFTER the registration of 600 additional Republicans and 500 additional Democrats, so it should be 1500-1200=300.

Re: In a certain district, the ratio of the number of registered [#permalink]
06 Mar 2013, 10:45

why cant we write it down as R/D = 3/5 and go further with (R+600)/(D+500). If we combine them we get R = 600 and D = 1000. Difference = 400. Whats wrong with this logic. Thanks in advance

Re: In a certain district, the ratio of the number of registered [#permalink]
07 Mar 2013, 01:29

Expert's post

mariofelixpasku wrote:

why cant we write it down as R/D = 3/5 and go further with (R+600)/(D+500). If we combine them we get R = 600 and D = 1000. Difference = 400. Whats wrong with this logic. Thanks in advance

Re: In a certain district, the ratio of the number of registered [#permalink]
10 Jul 2013, 05:37

1

This post received KUDOS

Expert's post

insidertrader wrote:

Hi, just wondering what is wrong with my approach as follows:

3/5 republican voters = 0.6*x Another 600 register as republican, with the total amount being 80% republican (4/5) Total new voters is 1,100 (500+600)

So, 0.6x + 600 = 0.8(x+1,100)

0.6x + 600 = 0.8x + 880

However, this is where I go awry.

Could someone pls explain why I can't use the approach noted above?

Thanks in advance

The ratio of Republicans to Democrats was 3:5, which means that Republicans were 3/(3+5)=3/8 of the total number (not 3/5 of the total number)

After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4:5, which means that that Republicans were 4/(4+5)=4/9 of the total number (not 4/5 of the total number).

3/8*x+600=4/9(x+1100) --> x=1600 --> after registration = x+1100=2700 --> Republicans=4/9*1200 and Democrats=1500 --> the difference=300.

Re: In a certain district, the ratio of the number of registered [#permalink]
10 Jul 2013, 05:45

Bunuel wrote:

insidertrader wrote:

Hi, just wondering what is wrong with my approach as follows:

3/5 republican voters = 0.6*x Another 600 register as republican, with the total amount being 80% republican (4/5) Total new voters is 1,100 (500+600)

So, 0.6x + 600 = 0.8(x+1,100)

0.6x + 600 = 0.8x + 880

However, this is where I go awry.

Could someone pls explain why I can't use the approach noted above?

Thanks in advance

The ratio of Republicans to Democrats was 3:5, which means that Republicans were 3/(3+5)=3/8 of the total number (not 3/5 of the total number)

After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4:5, which means that that Republicans were 4/(4+5)=4/9 of the total number (not 4/5 of the total number).

3/8*x+600=4/9(x+1100) --> x=1600 --> after registration = x+1100=2700 --> Republicans=4/9*1200 and Democrats=1500 --> the difference=300.

Re: In a certain district, the ratio of the number of registered [#permalink]
10 Jul 2013, 06:48

2

This post received KUDOS

Expert's post

If ever you're not seeing the math, you know one of the answers has to be correct, so you can just backsolve. Looking at the increase in numbers, it would make sense that the number of democrats MORE than republicans will probably be in the hundreds, so you'd likely start with B or C.

If you start with C: 400 is the difference between D's and R's in the new ratio: So there are 4x400 = 1600 Republicans and 5x400 = 2000 Democrats. If you subtract 600 from R and 500 from D, you get 1000 Republicans and 1500 Democrats, a 2/3 ratio. This isn't 3/5, but it's not far (66.7% vs 60%). The next attempt should be B since it's close but slightly too big:

B: 300 is the difference between D's and R's in the new ratio: So there are 4x300 = 1200 Republicans and 5x300 = 1500 Democrats. If you subtract 600 from R and 500 from D, you get 600 Republicans and 1000 Democrats, a 3/5 ratio. Bingo.

If you started with B, you got to the right answer quickly. If you started with A, D or E, your answer will be way off. While this is not a better solution than the algebraic one, sometimes it is easier to see.

Official guide problem solving Q 113 [#permalink]
14 Oct 2013, 00:59

In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4/5. After these registrations, there were how many more voters in the district registered as Democrats than as Republicans?

(A) 100 (B) 300 (C) 400 (D) 1,000 (E) 2,500

_________

My question is, why can't we take the multiplier which is 200, and multiply the new ratio 4/5 to get a difference of 200? Why is that wrong? that what was done In question 105 in the official guide. Thank you

Re: Official guide problem solving Q 113 [#permalink]
14 Oct 2013, 01:01

Expert's post

mjb2 wrote:

In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4/5. After these registrations, there were how many more voters in the district registered as Democrats than as Republicans?

(A) 100 (B) 300 (C) 400 (D) 1,000 (E) 2,500

_________

My question is, why can't we take the multiplier which is 200, and multiply the new ration 4/5 to get a difference of 200? Why is that wrong? In question 105 in the official guide that what was done. Thank you

Re: Official guide problem solving Q 113 [#permalink]
14 Oct 2013, 01:03

Expert's post

mjb2 wrote:

In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4/5. After these registrations, there were how many more voters in the district registered as Democrats than as Republicans?

(A) 100 (B) 300 (C) 400 (D) 1,000 (E) 2,500

_________

My question is, why can't we take the multiplier which is 200, and multiply the new ratio 4/5 to get a difference of 200? Why is that wrong? that what was done In question 105 in the official guide. Thank you

Merging similar topics. Please refer to the solutions above and ask if anything is unclear.

Re: In a certain district, the ratio of the number of registered [#permalink]
14 Oct 2013, 01:42

sorry for violating the rules.. I didn't really know them as this was my first post. Anyway, I still don't understand why we can not take the multiplier and multiply it by the new ration 4/5 (200*5)-(200*4)= 200 difference.

Re: In a certain district, the ratio of the number of registered [#permalink]
14 Oct 2013, 04:18

Expert's post

mjb2 wrote:

sorry for violating the rules.. I didn't really know them as this was my first post. Anyway, I still don't understand why we can not take the multiplier and multiply it by the new ration 4/5 (200*5)-(200*4)= 200 difference.

Sorry but I don't understand the logic behind your approach. _________________

Re: In a certain district, the ratio of the number of registered [#permalink]
16 Oct 2014, 08:36

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