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# In a certain game, a large container is filled with red,

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Director
Joined: 07 Nov 2004
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In a certain game, a large container is filled with red, [#permalink]  07 Jan 2005, 09:06
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In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 0

I do not have the OA, it is from the permuation course, practice question 5 in GMATClub.
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Director
Joined: 21 Sep 2004
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is finding the prime factors best way to approach such a question?
GMAT Club Legend
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Prime factorization is best approach. In 147000, forget about the 1000 part because there is no factor of 7 in there. Focus instead on 147 which is just 7^2 * 3. Answer is then 2 red beads worth 7 points each. It takes 10 seconds to do the problem.
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Best Regards,

Paul

Director
Joined: 21 Sep 2004
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thanks Paul. thats a damn good tip for such problems...
Director
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Paul wrote:
Prime factorization is best approach. In 147000, forget about the 1000 part because there is no factor of 7 in there. Focus instead on 147 which is just 7^2 * 3. Answer is then 2 red beads worth 7 points each. It takes 10 seconds to do the problem.

Paul, i am still lost here. Can you please elaborate? What if the question had been how many yellow, green, and blue beads were removed?
Director
Joined: 27 Dec 2004
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Paul, is there a general rule about when to use prime factorization?
VP
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[quote="gayathri"][quote="Paul"]Prime factorization is best approach. In 147000, forget about the 1000 part because there is no factor of 7 in there. Focus instead on 147 which is just 7^2 * 3. Answer is then 2 red beads worth 7 points each. It takes 10 seconds to do the problem.[/quote]

Paul, i am still lost here. Can you please elaborate? What if the question had been how many yellow, green, and blue beads were removed?
:oops:[/quote]

I wud say we can have all prime factors separated. Say a, b, c, d are no of beads removed in each case, then

7^a * 5^b * 3^c*2^d = 147000 in prime factors = 7^2 * 5^3* 3 * 2^3

So Red beads (a) = 2
Director
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Thanks Paul & Banerjeea!

I just realized why I did not understand the solution. The question says "If the product of the point values of the removed beads is 147,000, how many red beads were removed?" while I kept thinking sum of the point values
Current Student
Joined: 28 Dec 2004
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damn, key word product...got to lookout for that....LOL, i too thought it was a sum...thanks Paul and all...
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