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In a certain game, a large container is filled with red,

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In a certain game, a large container is filled with red, [#permalink] New post 30 Jan 2004, 17:29
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* In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 0
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 [#permalink] New post 30 Jan 2004, 17:35
147000 = 2^3 5^3 7^2 3^1

Answer is 9
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 [#permalink] New post 30 Jan 2004, 17:49
I didnt get u, I am weak in P&C. Please can u explain in detail.
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 [#permalink] New post 30 Jan 2004, 17:52
A'int u missing something..Zhung Gazi..

9 is not one among the options.

Vivek.
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 [#permalink] New post 30 Jan 2004, 17:58
I calculated total. But #red = 2
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 [#permalink] New post 30 Jan 2004, 18:14
Vivek, can u please tell me the official explanation and help me out
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 [#permalink] New post 30 Jan 2004, 18:28
Don't have the official explanation...but i gauge this from Zhung Gazi's explanation:

Factorize 147000 = 2^3 * 5^3 * 7^2 * 3^1

so to get the aforementioned number ... you remove 3 blue beads,5 yellow beads 1 green bead and 2 red beads

right Zhung Gazi ?
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 [#permalink] New post 30 Jan 2004, 18:37
That's correct. Thanks to unique factorization of a number.
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 [#permalink] New post 30 Jan 2004, 19:01
:thanks
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 [#permalink] New post 30 Jan 2004, 20:38
The question is asking how many Red Beads so the answer is D ( 7^2)
Total beads = 9
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 [#permalink] New post 31 Jan 2004, 09:24
I also got total 9 and 2 sevens (red)...Final Answer.
  [#permalink] 31 Jan 2004, 09:24
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