Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

29 Dec 2012, 05:10

10

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

5% (low)

Question Stats:

80% (02:17) correct
20% (01:43) wrong based on 956 sessions

HideShow timer Statistics

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

\(147,000=2^3*3*5^3*7^2\).

Since no other beads value is a multiple of 7, then there must be two red beads removed.

Re: In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

22 May 2014, 11:15

1

This post received KUDOS

Dear amarmeena1992

This is not a Combinations question. (And it cannot be, since you are not even told what the total number of balls is.)

You are told that the product of the scores of all the balls that were taken out is 147000. Now, \(147000 = 7^2*5^3*3*4*2^3\)

From this expression, you can easily deduce that:

2 Red balls were taken out (since each Red ball has a score of 7. So, number of Red balls = power of 7 in the expression), along with 3 Yellow balls, 1 Green ball and 3 Blue balls.

Hope this helps.
_________________

Please press Kudos if you were helped by my post!

Last edited by JapinderKaur on 22 May 2014, 13:37, edited 2 times in total.

Re: In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

22 May 2014, 12:01

1

This post received KUDOS

MavenQ wrote:

Dear amarmeena1992

This is not a Combinations question. (And it cannot be, since you are not even told what the total number of balls is.)

You are told that the product of the scores of all the balls that were taken out is 147000. Now, \(147000 = 7^2*5*3*4*2^3\)

From this expression, you can easily deduce that:

2 Red balls were taken out, along with 3 Yellow balls, 1 Green ball and 3 Blue balls.

Hope this helps.

Hi MavenQ, Kindly correct the factors : \(147,000 = 7^2*5^3*3*2^3\)

which would mean 2 R, 3 Y , 1 G and 3 B beads

Please press kudos if it helps you

Kudos is the best form of appreciation

Dear amarmeena1992, The beads R,Y,G,B are allotted some numbers which are prime. So now since the product of the values of removed beads are known, we can decompose or factorize the product into unique combination/product of the bead values as shown : 147,000 = 7*7*3*5*5*5*2*2*2 = \(7^2*5^3*3*2^3\)

that is 2 R, 3 Y , 1 G and 3 B Kudos is the best form of appreciation

Re: In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

08 Feb 2013, 10:31

It is easy after you recognize that you need to do a prime factorization. To make it easier the point values are prime numbers too. Tricky but we can do it!
_________________

I've failed over and over and over again in my life and that is why I succeed--Michael Jordan Kudos drives a person to better himself every single time. So Pls give it generously Wont give up till i hit a 700+

Re: In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

21 Feb 2014, 11:28

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

22 May 2014, 10:18

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed? A. 5 B. 4 C. 3 D. 2 E. 0

I am not able to comprehend the question correctly. There could be a lot of combinations for removing the beads. How could we find any particular answer?

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed? A. 5 B. 4 C. 3 D. 2 E. 0

I am not able to comprehend the question correctly. There could be a lot of combinations for removing the beads. How could we find any particular answer?

Merging similar topics. please refer to the discussion above and ask if anything remains unclear.

Re: In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

09 Jun 2014, 20:06

Bunuel wrote:

Walkabout wrote:

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

\(147,000=2^3*3*5^3*7^2\).

Since no other beads value is a multiple of 7, then there must be two red beads removed.

Now I know the correct answer but can you help me to understand what conceptual mistake did I do initially.

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

Initially I solved it like this:

14700 = 7 X 7 X 3 X 10^3

Since red bead is a multiple of 7 so I conclude that there were 7 red beads removed.
_________________

Like my post Send me a Kudos It is a Good manner. My Debrief: http://gmatclub.com/forum/how-to-score-750-and-750-i-moved-from-710-to-189016.html

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

\(147,000=2^3*3*5^3*7^2\).

Since no other beads value is a multiple of 7, then there must be two red beads removed.

Now I know the correct answer but can you help me to understand what conceptual mistake did I do initially.

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

Initially I solved it like this:

14700 = 7 X 7 X 3 X 10^3

Since red bead is a multiple of 7 so I conclude that there were 7 red beads removed.

Red beads worth 7 points. Say there were only 2 red beads removed. What would be the product of the point values of the removed beads? 7*7. If 7 red beads were removed the product would be 7*7*7*7*7*7*7.

In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

21 Jun 2015, 00:26

honchos wrote:

Bunuel wrote:

Walkabout wrote:

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

\(147,000=2^3*3*5^3*7^2\).

Since no other beads value is a multiple of 7, then there must be two red beads removed.

Now I know the correct answer but can you help me to understand what conceptual mistake did I do initially.

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

Initially I solved it like this:

14700 = 7 X 7 X 3 X 10^3

Since red bead is a multiple of 7 so I conclude that there were 7 red beads removed.

Initially I did the same mistake... But then I saw number 7 suits none of the answer choices but it should be the correct logic, as I did factorization, so it must be 2 One must read carefully, it says the PRODUCT of the removed beads, so 49 = 7*7 --> 2 Red beads
_________________

When you’re up, your friends know who you are. When you’re down, you know who your friends are.

Share some Kudos, if my posts help you. Thank you !

Re: In a certain game, a large container is filled with red, yel [#permalink]

Show Tags

15 Jul 2016, 03:43

Walkabout wrote:

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5 (B) 4 (C) 3 (D) 2 (E) 0

The first thing we want to do is to decipher the problem. The key word here is “product;" we are told that the product of the point values of the removed beads is 147,000.

Let's look at an example. Let’s say 2 red beads, 2 yellow beads, 2 green beads, and 2 blue beads were removed. The product of the point values would be:

7 x 7 x 5 x 5 x 3 x 3 x 2 x 2 = 44,100

Conversely, if we were to take 44,100 and break it down into its prime factors, we would get:

44,100 = 7 x 7 x 5 x 5 x 3 x 3 x 2 x 2

Note that this prime factorization of 44,100 corresponds exactly to the point values of the 2 red beads, the 2 yellow beads, the 2 green beads, and the 2 blue beads from the example.

This example is important because we can now use the same approach for answering the actual question. We are given that the product of the point values of the removed beads is 147,000. Thus, some number of 7’s, 5’s, 3’s, and 2’s is multiplied together to equal 147,000. Since we only care about the red beads, we only care about the number of 7’s in the product. Let’s keep this in mind as we break down 147,000.

147,000 = 147 x 1,000 = 49 x 3 x 1,000 = 7 x 7 x 3 x 1,000

Since 1,000 does not have 7 as a factor, we see that there are two 7’s in the product of 147,000; thus, 2 red beads were removed.

The answer is D.
_________________

Jeffrey Miller Scott Woodbury-Stewart Founder and CEO

gmatclubot

Re: In a certain game, a large container is filled with red, yel
[#permalink]
15 Jul 2016, 03:43

Happy New Year everyone! Before I get started on this post, and well, restarted on this blog in general, I wanted to mention something. For the past several months...

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Happy 2017! Here is another update, 7 months later. With this pace I might add only one more post before the end of the GSB! However, I promised that...