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In a certain game, a large container is filled with red, yel [#permalink]
29 Dec 2012, 05:10
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Question Stats:
80% (02:14) correct
20% (01:41) wrong based on 602 sessions
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
Re: In a certain game, a large container is filled with red, yel [#permalink]
29 Dec 2012, 05:14
5
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Expert's post
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Walkabout wrote:
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5 (B) 4 (C) 3 (D) 2 (E) 0
\(147,000=2^3*3*5^3*7^2\).
Since no other beads value is a multiple of 7, then there must be two red beads removed.
Re: In a certain game, a large container is filled with red, yel [#permalink]
08 Feb 2013, 10:31
It is easy after you recognize that you need to do a prime factorization. To make it easier the point values are prime numbers too. Tricky but we can do it! _________________
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Re: In a certain game, a large container is filled with red, yel [#permalink]
21 Feb 2014, 11:28
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In a certain game, a large container is filled with red, yel [#permalink]
22 May 2014, 10:18
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed? A. 5 B. 4 C. 3 D. 2 E. 0
I am not able to comprehend the question correctly. There could be a lot of combinations for removing the beads. How could we find any particular answer?
Re: In a certain game, a large container is filled with red, yel [#permalink]
22 May 2014, 10:29
Expert's post
2
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amarmeena1992 wrote:
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed? A. 5 B. 4 C. 3 D. 2 E. 0
I am not able to comprehend the question correctly. There could be a lot of combinations for removing the beads. How could we find any particular answer?
Merging similar topics. please refer to the discussion above and ask if anything remains unclear.
Re: In a certain game, a large container is filled with red, yel [#permalink]
22 May 2014, 11:15
1
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Dear amarmeena1992
This is not a Combinations question. (And it cannot be, since you are not even told what the total number of balls is.)
You are told that the product of the scores of all the balls that were taken out is 147000. Now, \(147000 = 7^2*5^3*3*4*2^3\)
From this expression, you can easily deduce that:
2 Red balls were taken out (since each Red ball has a score of 7. So, number of Red balls = power of 7 in the expression), along with 3 Yellow balls, 1 Green ball and 3 Blue balls.
Hope this helps. _________________
Please press Kudos if you were helped by my post!
Last edited by MavenQ on 22 May 2014, 13:37, edited 2 times in total.
Re: In a certain game, a large container is filled with red, yel [#permalink]
22 May 2014, 12:01
1
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MavenQ wrote:
Dear amarmeena1992
This is not a Combinations question. (And it cannot be, since you are not even told what the total number of balls is.)
You are told that the product of the scores of all the balls that were taken out is 147000. Now, \(147000 = 7^2*5*3*4*2^3\)
From this expression, you can easily deduce that:
2 Red balls were taken out, along with 3 Yellow balls, 1 Green ball and 3 Blue balls.
Hope this helps.
Hi MavenQ, Kindly correct the factors : \(147,000 = 7^2*5^3*3*2^3\)
which would mean 2 R, 3 Y , 1 G and 3 B beads
Please press kudos if it helps you
Kudos is the best form of appreciation
Dear amarmeena1992, The beads R,Y,G,B are allotted some numbers which are prime. So now since the product of the values of removed beads are known, we can decompose or factorize the product into unique combination/product of the bead values as shown : 147,000 = 7*7*3*5*5*5*2*2*2 = \(7^2*5^3*3*2^3\)
that is 2 R, 3 Y , 1 G and 3 B Kudos is the best form of appreciation
Re: In a certain game, a large container is filled with red, yel [#permalink]
09 Jun 2014, 20:06
Bunuel wrote:
Walkabout wrote:
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5 (B) 4 (C) 3 (D) 2 (E) 0
\(147,000=2^3*3*5^3*7^2\).
Since no other beads value is a multiple of 7, then there must be two red beads removed.
Now I know the correct answer but can you help me to understand what conceptual mistake did I do initially.
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5 (B) 4 (C) 3 (D) 2 (E) 0
Initially I solved it like this:
14700 = 7 X 7 X 3 X 10^3
Since red bead is a multiple of 7 so I conclude that there were 7 red beads removed. _________________
Re: In a certain game, a large container is filled with red, yel [#permalink]
10 Jun 2014, 00:33
Expert's post
honchos wrote:
Bunuel wrote:
Walkabout wrote:
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5 (B) 4 (C) 3 (D) 2 (E) 0
\(147,000=2^3*3*5^3*7^2\).
Since no other beads value is a multiple of 7, then there must be two red beads removed.
Now I know the correct answer but can you help me to understand what conceptual mistake did I do initially.
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5 (B) 4 (C) 3 (D) 2 (E) 0
Initially I solved it like this:
14700 = 7 X 7 X 3 X 10^3
Since red bead is a multiple of 7 so I conclude that there were 7 red beads removed.
Red beads worth 7 points. Say there were only 2 red beads removed. What would be the product of the point values of the removed beads? 7*7. If 7 red beads were removed the product would be 7*7*7*7*7*7*7.
In a certain game, a large container is filled with red, yel [#permalink]
21 Jun 2015, 00:26
honchos wrote:
Bunuel wrote:
Walkabout wrote:
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5 (B) 4 (C) 3 (D) 2 (E) 0
\(147,000=2^3*3*5^3*7^2\).
Since no other beads value is a multiple of 7, then there must be two red beads removed.
Now I know the correct answer but can you help me to understand what conceptual mistake did I do initially.
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
(A) 5 (B) 4 (C) 3 (D) 2 (E) 0
Initially I solved it like this:
14700 = 7 X 7 X 3 X 10^3
Since red bead is a multiple of 7 so I conclude that there were 7 red beads removed.
Initially I did the same mistake... But then I saw number 7 suits none of the answer choices but it should be the correct logic, as I did factorization, so it must be 2 One must read carefully, it says the PRODUCT of the removed beads, so 49 = 7*7 --> 2 Red beads _________________
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