Find all School-related info fast with the new School-Specific MBA Forum

It is currently 24 Oct 2014, 16:16

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In a certain game, a large container is filled with red, yellow, green

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
1 KUDOS received
Eternal Intern
User avatar
Joined: 07 Jun 2003
Posts: 479
Location: Lone Star State
Followers: 1

Kudos [?]: 20 [1] , given: 0

In a certain game, a large container is filled with red, yellow, green [#permalink] New post 19 Jun 2003, 13:24
1
This post received
KUDOS
1
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

61% (01:58) correct 39% (01:21) wrong based on 63 sessions
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 0

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-certain-game-a-large-container-is-filled-with-red-yel-144902.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Sep 2014, 11:59, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
Kaplan Promo CodeKnewton GMAT Discount CodesGMAT Pill GMAT Discount Codes
3 KUDOS received
Manager
Manager
User avatar
Joined: 18 Jun 2003
Posts: 142
Location: Hockeytown
Followers: 1

Kudos [?]: 13 [3] , given: 0

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 19 Jun 2003, 17:04
3
This post received
KUDOS
Curly05 wrote:
. In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?


I get 2.

First I simplified 147,000 to 147.
147 divides by 3, since 1+4+7 is divisible by 3.
147 divided by 3 = 49, which in turn equals 7x7.

So 7x7x3 = 147.

Now we need to get 147 to equal 147,000. We do this by multiplying 147 x 1000.
To get 1000, multiply (5x2)x(5x2)x(5x2).

So you have 7x7x3x5x2x5x2x5x2 = RxRxGxYxBxYxBxYxB

So there are:
2R
1G
3Y
3B
Expert Post
Founder
Founder
User avatar
Affiliations: UA-1K, SPG-G, HH-D
Joined: 04 Dec 2002
Posts: 12349
Location: United States (WA)
GMAT 1: 750 Q49 V42
GPA: 3.5
WE: Information Technology (Hospitality and Tourism)
Followers: 2325

Kudos [?]: 9454 [0], given: 3702

GMAT ToolKit User Premium Member CAT Tests
Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 24 Jun 2003, 23:04
Expert's post
EASY STUFF :oops:
Expert Post
SVP
SVP
avatar
Status: Graduated
Affiliations: HEC
Joined: 28 Sep 2009
Posts: 1638
Concentration: Economics, Finance
GMAT 1: 730 Q48 V44
Followers: 86

Kudos [?]: 490 [0], given: 432

Premium Member
Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 06 Oct 2009, 10:22
Expert's post
JP, you make it so easy to understand. I'm beginning to realize now what people have been telling me on these forums: the math uses basic concepts. The more difficult problems are just dressed up in something scary.



But I still freak out sometimes.
_________________

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Intern
Intern
avatar
Joined: 17 Jun 2010
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 17 Jun 2010, 10:55
I think the easiest way of thinking about it is factor out seven as many times as you can (each time you factor out a seven you're counting a red ball). 147000/7=21000, 21000/7=3000, and it's pretty easy to see (or check) that 3000 is some multiple of 2,3, and 5.
1 KUDOS received
Manager
Manager
avatar
Joined: 19 Apr 2010
Posts: 214
Schools: ISB, HEC, Said
Followers: 4

Kudos [?]: 20 [1] , given: 28

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 23 Sep 2010, 04:15
1
This post received
KUDOS
7, 5, 3, and 2 are all prime numbers. We need to decompose the 147,000 into these prime factors
Senior Manager
Senior Manager
avatar
Joined: 06 Jun 2009
Posts: 333
Location: USA
WE 1: Engineering
Followers: 1

Kudos [?]: 56 [0], given: 0

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 23 Sep 2010, 07:18
1
This post was
BOOKMARKED
bb wrote:
EASY STUFF :oops:


The title really freaked me out .......... it was like - "OK, if I get this, maybe the preparation is not too bad". After I read the question :!:

147,000 = 7 x 7 x 5 x 5 x 5 x 3 x 2 x 2 x 2

Therefore, 2 Red , 3 Yellow, 1 Green & 3 Blue.
_________________

All things are possible to those who believe.

Senior Manager
Senior Manager
avatar
Joined: 20 Jul 2010
Posts: 271
Followers: 2

Kudos [?]: 40 [0], given: 9

GMAT ToolKit User Reviews Badge
Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 23 Sep 2010, 12:25
We have to find number of Red beads which are associated with 7

147000 = 7 X 7 X 3 X 1000
Number of Red = 2
_________________

If you like my post, consider giving me some KUDOS !!!!! Like you I need them

Intern
Intern
avatar
Joined: 17 Jun 2008
Posts: 7
Followers: 0

Kudos [?]: 0 [0], given: 1

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 05 Jan 2011, 17:47
You psyched yourself out. A question like this can and should be easily done in under a minute. A light bulb should turn on as you think...What's the concept here...AHA! FACTORIZATION! If that light bulb doesn't go off, you are not prepared enough, because virtually every GMAT problem has a label.
Senior Manager
Senior Manager
avatar
Status: Up again.
Joined: 31 Oct 2010
Posts: 491
Location: India
GMAT 1: 740 Q49 V42
WE: Project Management (Manufacturing)
Followers: 13

Kudos [?]: 68 [0], given: 75

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 05 Jan 2011, 21:10
I've seen this problem in some book.. I think MGMAT number properties.. And I've seen another versions of the same concept elsewhere too.

BTW yes, its been very nicely explained above. The key here is indeed understanding that the problem is just calling for prime factorization.
_________________

My GMAT debrief: from-620-to-710-my-gmat-journey-114437.html

Manager
Manager
avatar
Joined: 08 Jun 2011
Posts: 98
Followers: 1

Kudos [?]: 17 [0], given: 65

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 13 Aug 2011, 12:15
It seems to me that 2 is the straight forward answer. However, after I factored this, I ended up with 4

The factorization of 147 yields 7 * 21 which should be factored into 3 * 7.

Now, doesn't 21 have three 7s in it? Along with the original seven we will end up with four sevens.

I know that multiplying four 7s together will give us a higher number than 147, but why didn't we go with what I explained?
Director
Director
User avatar
Joined: 03 May 2007
Posts: 899
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 52 [0], given: 7

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 13 Aug 2011, 18:40
Curly05 wrote:
. In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?


= 147,000
= 147 x 1000
= (3) x (7x7) x (2x2x2) x (5x5x5)
= 2^3 x 3^1 x 5^3 x 7^2

red = 7^2 = 49
Intern
Intern
avatar
Joined: 04 Oct 2010
Posts: 38
Location: United States
GMAT 1: Q V
GMAT 2: Q V
GMAT 3: 760 Q49 V45
WE: Consulting (Consulting)
Followers: 0

Kudos [?]: 12 [0], given: 1

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 17 Aug 2011, 10:11
Is it just me or are there no answer choices posted? Without looking at the answer choices you can't determine the solution. For example you could remove 21,000 red beads and no others, which would give a total of 147,000. If this were on the GMAT I think they would give a limit to the number of beads of each color or make it obvious from the answer choices how to approach it.
Math Forum Moderator
avatar
Joined: 20 Dec 2010
Posts: 2037
Followers: 128

Kudos [?]: 956 [0], given: 376

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 17 Aug 2011, 11:21
mj12g wrote:
Is it just me or are there no answer choices posted? Without looking at the answer choices you can't determine the solution. For example you could remove 21,000 red beads and no others, which would give a total of 147,000. If this were on the GMAT I think they would give a limit to the number of beads of each color or make it obvious from the answer choices how to approach it.


There is only one answer per the given conditions. No need of options.

We can definitely say that only 2 red beads were removed, no more no less. We can deduce that by seeing the exponent of 7, which is 2.

147000=2^3*3*5^3*7^2

Ans: "2"
_________________

~fluke

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Intern
Intern
avatar
Joined: 20 Feb 2012
Posts: 1
Followers: 0

Kudos [?]: 1 [0], given: 0

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 05 Apr 2012, 13:19
fluke wrote:
mj12g wrote:
Is it just me or are there no answer choices posted? Without looking at the answer choices you can't determine the solution. For example you could remove 21,000 red beads and no others, which would give a total of 147,000. If this were on the GMAT I think they would give a limit to the number of beads of each color or make it obvious from the answer choices how to approach it.


There is only one answer per the given conditions. No need of options.

We can definitely say that only 2 red beads were removed, no more no less. We can deduce that by seeing the exponent of 7, which is 2.

147000=2^3*3*5^3*7^2

Ans: "2"


Right, this is because the question stem says 'product' of the point values. In the example where we remove 21,000 red beads, the total must be calculated as the product of the point values for 21,000 beads which is 7^21,000. A truly massive number!
Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 23409
Followers: 3613

Kudos [?]: 28917 [1] , given: 2871

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 05 Apr 2012, 13:29
1
This post received
KUDOS
Expert's post
Curly05 wrote:
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?


Check similar question to practice: in-a-certain-game-a-large-bag-is-filled-with-blue-green-126425.html
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Intern
Intern
avatar
Joined: 01 May 2013
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 01 May 2013, 02:37
Not sure if Red = 2 is the only answer.
Other answers:
Red = 7 (with Y, G, B as 4, 5 , 5)
Red = 5 ( with Y, G, B as 7, 2, 10)
Red = 4 (with Y, G, B as 5, 5, 7)
Red = 2 (with Y, G, B as 10, 5, 7)
(values of Y, G, B in any sequence)

And if Red = 2, then by default, is Red = 4 not also possible?

What if no Reds have been taken out? Surely Red = 0 is also possible?

Let me know what you think.
Expert Post
Verbal Forum Moderator
Verbal Forum Moderator
User avatar
Joined: 10 Oct 2012
Posts: 628
Followers: 43

Kudos [?]: 598 [0], given: 135

Premium Member
Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 01 May 2013, 07:36
Expert's post
EdNyhof wrote:
Not sure if Red = 2 is the only answer.
Other answers:
Red = 7 (with Y, G, B as 4, 5 , 5)
Red = 5 ( with Y, G, B as 7, 2, 10)
Red = 4 (with Y, G, B as 5, 5, 7)
Red = 2 (with Y, G, B as 10, 5, 7)
(values of Y, G, B in any sequence)

And if Red = 2, then by default, is Red = 4 not also possible?


What if no Reds have been taken out? Surely Red = 0 is also possible?

Let me know what you think.


Is not clear what you mean by that.The problem states "product of the point values of the removed beads is 147,000."All the given points (2,3,5,7) are primes. The given point value is 147,000 = 49*30*100 = 7^2*5^3*2^3*3. Now if I would have removed one yellow bead and one blue bead, the product of the points would be = 5*2. Thus, in no other way can you get a factor of 7, if you don't pick up 2 red beads.
_________________

All that is equal and not-Deep Dive In-equality

Hit and Trial for Integral Solutions

Intern
Intern
avatar
Status: Grad Student
Joined: 08 Sep 2013
Posts: 1
Location: United States
Concentration: Technology, General Management
GPA: 3.87
WE: Information Technology (Education)
Followers: 0

Kudos [?]: 5 [0], given: 2

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 19 Sep 2013, 17:32
mau5 wrote:
EdNyhof wrote:
Not sure if Red = 2 is the only answer.
Other answers:
Red = 7 (with Y, G, B as 4, 5 , 5)
Red = 5 ( with Y, G, B as 7, 2, 10)
Red = 4 (with Y, G, B as 5, 5, 7)
Red = 2 (with Y, G, B as 10, 5, 7)
(values of Y, G, B in any sequence)

And if Red = 2, then by default, is Red = 4 not also possible?


What if no Reds have been taken out? Surely Red = 0 is also possible?

Let me know what you think.


Is not clear what you mean by that.The problem states "product of the point values of the removed beads is 147,000."All the given points (2,3,5,7) are primes. The given point value is 147,000 = 49*30*100 = 7^2*5^3*2^3*3. Now if I would have removed one yellow bead and one blue bead, the product of the points would be = 5*2. Thus, in no other way can you get a factor of 7, if you don't pick up 2 red beads.



Could you please explain how you got this: [color=#ff0000]7^2*5^3*2^3*3[/color] ?
Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 23409
Followers: 3613

Kudos [?]: 28917 [1] , given: 2871

Re: In a certain game, a large container is filled with red, yellow, green [#permalink] New post 20 Sep 2013, 00:50
1
This post received
KUDOS
Expert's post
azizf60 wrote:
mau5 wrote:
EdNyhof wrote:
Not sure if Red = 2 is the only answer.
Other answers:
Red = 7 (with Y, G, B as 4, 5 , 5)
Red = 5 ( with Y, G, B as 7, 2, 10)
Red = 4 (with Y, G, B as 5, 5, 7)
Red = 2 (with Y, G, B as 10, 5, 7)
(values of Y, G, B in any sequence)

And if Red = 2, then by default, is Red = 4 not also possible?


What if no Reds have been taken out? Surely Red = 0 is also possible?

Let me know what you think.


Is not clear what you mean by that.The problem states "product of the point values of the removed beads is 147,000."All the given points (2,3,5,7) are primes. The given point value is 147,000 = 49*30*100 = 7^2*5^3*2^3*3. Now if I would have removed one yellow bead and one blue bead, the product of the points would be = 5*2. Thus, in no other way can you get a factor of 7, if you don't pick up 2 red beads.



Could you please explain how you got this: [color=#ff0000]7^2*5^3*2^3*3[/color] ?


2^3*3*5^3*7^2is prime factorization of 147,000 = 1,000*147 = (8*125)*(3*49) = 2^3*3*5^3*7^2.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Re: In a certain game, a large container is filled with red, yellow, green   [#permalink] 20 Sep 2013, 00:50
    Similar topics Author Replies Last post
Similar
Topics:
In a certain game, a large container is filled with red, girikorat 9 09 Oct 2006, 10:14
In a certain game, a large container is filled with red, Rayn 19 08 Jul 2006, 19:13
In a certain game, a large container is filled with red, alimad 3 26 May 2006, 19:03
In a certain game, a large container is filled with red, allabout 9 22 Dec 2005, 04:36
In a certain game, a large container is filled with red, gayathri 8 07 Jan 2005, 09:06
Display posts from previous: Sort by

In a certain game, a large container is filled with red, yellow, green

  Question banks Downloads My Bookmarks Reviews Important topics  

Go to page    1   2    Next  [ 22 posts ] 



GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.