Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

19 Jun 2003, 14:24

1

This post received KUDOS

4

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

5% (low)

Question Stats:

73% (02:04) correct
27% (01:15) wrong based on 173 sessions

HideShow timer Statictics

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

19 Jun 2003, 18:04

4

This post received KUDOS

2

This post was BOOKMARKED

Curly05 wrote:

. In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

I get 2.

First I simplified 147,000 to 147.
147 divides by 3, since 1+4+7 is divisible by 3.
147 divided by 3 = 49, which in turn equals 7x7.

So 7x7x3 = 147.

Now we need to get 147 to equal 147,000. We do this by multiplying 147 x 1000.
To get 1000, multiply (5x2)x(5x2)x(5x2).

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

06 Oct 2009, 11:22

Expert's post

JP, you make it so easy to understand. I'm beginning to realize now what people have been telling me on these forums: the math uses basic concepts. The more difficult problems are just dressed up in something scary.

But I still freak out sometimes. _________________

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

17 Jun 2010, 11:55

I think the easiest way of thinking about it is factor out seven as many times as you can (each time you factor out a seven you're counting a red ball). 147000/7=21000, 21000/7=3000, and it's pretty easy to see (or check) that 3000 is some multiple of 2,3, and 5.

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

05 Jan 2011, 18:47

You psyched yourself out. A question like this can and should be easily done in under a minute. A light bulb should turn on as you think...What's the concept here...AHA! FACTORIZATION! If that light bulb doesn't go off, you are not prepared enough, because virtually every GMAT problem has a label.

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

05 Jan 2011, 22:10

I've seen this problem in some book.. I think MGMAT number properties.. And I've seen another versions of the same concept elsewhere too.

BTW yes, its been very nicely explained above. The key here is indeed understanding that the problem is just calling for prime factorization. _________________

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

13 Aug 2011, 19:40

Curly05 wrote:

. In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

= 147,000 = 147 x 1000 = (3) x (7x7) x (2x2x2) x (5x5x5) = 2^3 x 3^1 x 5^3 x 7^2

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

17 Aug 2011, 11:11

Is it just me or are there no answer choices posted? Without looking at the answer choices you can't determine the solution. For example you could remove 21,000 red beads and no others, which would give a total of 147,000. If this were on the GMAT I think they would give a limit to the number of beads of each color or make it obvious from the answer choices how to approach it.

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

17 Aug 2011, 12:21

mj12g wrote:

Is it just me or are there no answer choices posted? Without looking at the answer choices you can't determine the solution. For example you could remove 21,000 red beads and no others, which would give a total of 147,000. If this were on the GMAT I think they would give a limit to the number of beads of each color or make it obvious from the answer choices how to approach it.

There is only one answer per the given conditions. No need of options.

We can definitely say that only 2 red beads were removed, no more no less. We can deduce that by seeing the exponent of 7, which is 2.

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

05 Apr 2012, 14:19

fluke wrote:

mj12g wrote:

Is it just me or are there no answer choices posted? Without looking at the answer choices you can't determine the solution. For example you could remove 21,000 red beads and no others, which would give a total of 147,000. If this were on the GMAT I think they would give a limit to the number of beads of each color or make it obvious from the answer choices how to approach it.

There is only one answer per the given conditions. No need of options.

We can definitely say that only 2 red beads were removed, no more no less. We can deduce that by seeing the exponent of 7, which is 2.

\(147000=2^3*3*5^3*7^2\)

Ans: "2"

Right, this is because the question stem says 'product' of the point values. In the example where we remove 21,000 red beads, the total must be calculated as the product of the point values for 21,000 beads which is 7^21,000. A truly massive number!

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

05 Apr 2012, 14:29

1

This post received KUDOS

Expert's post

Curly05 wrote:

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

01 May 2013, 03:37

Not sure if Red = 2 is the only answer. Other answers: Red = 7 (with Y, G, B as 4, 5 , 5) Red = 5 ( with Y, G, B as 7, 2, 10) Red = 4 (with Y, G, B as 5, 5, 7) Red = 2 (with Y, G, B as 10, 5, 7) (values of Y, G, B in any sequence)

And if Red = 2, then by default, is Red = 4 not also possible?

What if no Reds have been taken out? Surely Red = 0 is also possible?

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

01 May 2013, 08:36

Expert's post

EdNyhof wrote:

Not sure if Red = 2 is the only answer. Other answers: Red = 7 (with Y, G, B as 4, 5 , 5) Red = 5 ( with Y, G, B as 7, 2, 10) Red = 4 (with Y, G, B as 5, 5, 7) Red = 2 (with Y, G, B as 10, 5, 7) (values of Y, G, B in any sequence) And if Red = 2, then by default, is Red = 4 not also possible?

What if no Reds have been taken out? Surely Red = 0 is also possible?

Let me know what you think.

Is not clear what you mean by that.The problem states "product of the point values of the removed beads is 147,000."All the given points (2,3,5,7) are primes. The given point value is 147,000 = 49*30*100 = \(7^2*5^3*2^3*3\). Now if I would have removed one yellow bead and one blue bead, the product of the points would be = 5*2. Thus, in no other way can you get a factor of 7, if you don't pick up 2 red beads. _________________

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

19 Sep 2013, 18:32

mau5 wrote:

EdNyhof wrote:

Not sure if Red = 2 is the only answer. Other answers: Red = 7 (with Y, G, B as 4, 5 , 5) Red = 5 ( with Y, G, B as 7, 2, 10) Red = 4 (with Y, G, B as 5, 5, 7) Red = 2 (with Y, G, B as 10, 5, 7) (values of Y, G, B in any sequence) And if Red = 2, then by default, is Red = 4 not also possible?

What if no Reds have been taken out? Surely Red = 0 is also possible?

Let me know what you think.

Is not clear what you mean by that.The problem states "product of the point values of the removed beads is 147,000."All the given points (2,3,5,7) are primes. The given point value is 147,000 = 49*30*100 = \(7^2*5^3*2^3*3\). Now if I would have removed one yellow bead and one blue bead, the product of the points would be = 5*2. Thus, in no other way can you get a factor of 7, if you don't pick up 2 red beads.

Could you please explain how you got this: [color=#ff0000]7^2*5^3*2^3*3[/color] ?

Re: In a certain game, a large container is filled with red, yellow, green [#permalink]

Show Tags

20 Sep 2013, 01:50

1

This post received KUDOS

Expert's post

azizf60 wrote:

mau5 wrote:

EdNyhof wrote:

Not sure if Red = 2 is the only answer. Other answers: Red = 7 (with Y, G, B as 4, 5 , 5) Red = 5 ( with Y, G, B as 7, 2, 10) Red = 4 (with Y, G, B as 5, 5, 7) Red = 2 (with Y, G, B as 10, 5, 7) (values of Y, G, B in any sequence) And if Red = 2, then by default, is Red = 4 not also possible?

What if no Reds have been taken out? Surely Red = 0 is also possible?

Let me know what you think.

Is not clear what you mean by that.The problem states "product of the point values of the removed beads is 147,000."All the given points (2,3,5,7) are primes. The given point value is 147,000 = 49*30*100 = \(7^2*5^3*2^3*3\). Now if I would have removed one yellow bead and one blue bead, the product of the points would be = 5*2. Thus, in no other way can you get a factor of 7, if you don't pick up 2 red beads.

Could you please explain how you got this: [color=#ff0000]7^2*5^3*2^3*3[/color] ?

\(2^3*3*5^3*7^2\)is prime factorization of \(147,000 = 1,000*147 = (8*125)*(3*49) = 2^3*3*5^3*7^2\). _________________

So, my final tally is in. I applied to three b schools in total this season: INSEAD – admitted MIT Sloan – admitted Wharton – waitlisted and dinged No...

HBS alum talks about effective altruism and founding and ultimately closing MBAs Across America at TED: Casey Gerald speaks at TED2016 – Dream, February 15-19, 2016, Vancouver Convention Center...