Find all School-related info fast with the new School-Specific MBA Forum

It is currently 02 Sep 2015, 03:11
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In a certain game played with red chips and blue chips, each

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Intern
Intern
avatar
Joined: 02 Sep 2010
Posts: 48
WE 1: Business Development Manger
WE 2: Assistant Manager-Carbon Trading
WE 3: Manager-Carbon Trading
Followers: 2

Kudos [?]: 21 [0], given: 16

In a certain game played with red chips and blue chips, each [#permalink] New post 25 Nov 2010, 00:58
2
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  75% (hard)

Question Stats:

55% (03:04) correct 45% (01:57) wrong based on 102 sessions
In a certain game played with red chips and blue chips, each red chip has a point value of X and each blue chip has a point value of Y, where X>Y and X and Y are positive integers. If a player has 5 red chips and 3 blue chips, what is the average (arithmetic mean ) point value of the 8 chips that the player has?

(1) The average point value of one red chip and one blue chip is 5.
(2) The average point value of the 8 chips that the player has is an integer.
[Reveal] Spoiler: OA
Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 29186
Followers: 4737

Kudos [?]: 50071 [1] , given: 7527

Re: Question [#permalink] New post 25 Nov 2010, 01:11
1
This post received
KUDOS
Expert's post
rite2deepti wrote:
In a certain game played with red chips and blue chips, each red chip has a point value of X and each blue chip has a point value of Y, where X>Y and X and Y are positive integers. If a player has 5 red chips and 3 blue chips, what is the average (arithmetic mean ) point value of the 8 chips that the player has?

(1) The average point value of one red chip and one blue chip is 5.
(2) The average point value of the 8 chips that the player has is an integer.

I am absolutely clueless about this question ...how to proceed ..Also please explain in detail


Given: \(x=integer>y=integer>0\). Question: \(\frac{5x+3y}{8}=?\)

(1) The average point value of one red chip and one blue chip is 5 --> \(\frac{x+y}{2}=5\) --> \(x=10-y\) --> \(\frac{5x+3y}{8}=\frac{50-5y+3y}{8}=\frac{50-2y}{8}=\frac{25-y}{4}=?\), still need the value of \(y\). Not sufficient.

(2) The average point value of the 8 chips that the player has is an integer --> \(\frac{5x+3y}{8}=integer\). Clearly insufficient.

(1)+(2) From (1) and (2) we have that \(\frac{25-y}{4}=integer\) and \(x=10-y\). Now, \(\frac{25-y}{4}=integer\) to be true \(y\) must be 1 (in this case \(x=10-y=9\)), 5 (in this case \(x=10-y=5\)), or 9 (in this case \(x=10-y=1\)). But as given that \(x>y\) then only value of \(y\) is valid, namely \(y=1\) --> \(\frac{25-y}{4}=6\). Sufficient.

Answer: C.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis ; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) ; 12. Tricky questions from previous years.

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

GMAT Club Premium Membership - big benefits and savings

Manager
Manager
avatar
Joined: 11 Jul 2010
Posts: 228
Followers: 1

Kudos [?]: 58 [0], given: 20

GMAT ToolKit User
Re: Question [#permalink] New post 25 Nov 2010, 01:12
should be C

R's value = 6 and B's value = 4 satisfies; R's value = 11 also satisfies but R+B = 10 as per (1) so R=11 can not be taken
Expert Post
1 KUDOS received
Veritas Prep GMAT Instructor
User avatar
Joined: 16 Oct 2010
Posts: 5866
Location: Pune, India
Followers: 1481

Kudos [?]: 7979 [1] , given: 190

Re: Question [#permalink] New post 25 Nov 2010, 21:42
1
This post received
KUDOS
Expert's post
rite2deepti wrote:
In a certain game played with red chips and blue chips, each red chip has a point value
of X and each blue chip has a point value of Y, where X>Y and X and Y are positive
integers. If a player has 5 red chips and 3 blue chips, what is the average (arithmetic
mean ) point value of the 8 chips that the player has?

(1) The average point value of one red chip and one blue chip is 5.
(2) The average point value of the 8 chips that the player has is an integer.

I am absolutely clueless about this question ...how to proceed ..Also please explain in detail


If algebra doesn't work for you, go on and use brute force.
Simply try to arrange the information you have:
Red - X points Blue - Y points
X > Y, X and Y are +ve integer (You kind of expect it from a regular game so nothing to remember here)
5 Red ..... 3 Blue

Statement 1: Average point value of 1 Red and 1 Blue chip is 5, their total point value will be 5*2 = 10

So only 4 cases possible:
1 Red (9).... 1 Blue (1)
1 Red (8).... 1 Blue (2)
1 Red (7).... 1 Blue (3)
1 Red (6).... 1 Blue (4)
Average of 5 reds and 3 blues will be different in each case so not sufficient.

Statement 2: Average of 8 chips is integer. Insufficient alone.

Both statements together:
Case 1: 1 Red (9).... 1 Blue (1): 5 Red + 3 Blue = 48 - Divisible by 8
Case 2: 1 Red (8).... 1 Blue (2): 5 Red + 3 Blue = 46 - Not div by 8
Case 3: 1 Red (7).... 1 Blue (3): 5 Red + 3 Blue = 44 - Not div by 8
See the pattern, next one will be 42 - Not div by 8
Since in only one case, we get the average of 8 chips an integer, both together are sufficient. Answer (C).
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199

Veritas Prep Reviews

GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 6174
Followers: 344

Kudos [?]: 70 [0], given: 0

Premium Member
Re: In a certain game played with red chips and blue chips, each [#permalink] New post 24 Mar 2014, 03:19
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

SVP
SVP
User avatar
Joined: 06 Sep 2013
Posts: 2046
Concentration: Finance
GMAT 1: 770 Q0 V
Followers: 32

Kudos [?]: 345 [0], given: 355

GMAT ToolKit User
Re: In a certain game played with red chips and blue chips, each [#permalink] New post 26 Mar 2014, 07:46
OK so just to clarify this question and move on..

Now first statement only tells us that x+y=10. Clearly insufficient. Statement 2 tells us that 5x+3y has to be a multiple of 8, which again can happen in many ways, say x=4 and y=3 or x=9 and y=1. Therefore insufficient. From both statement together we have that x+y=10 therefore only the second option x-9 and y=1 is possible. C stands as the correct answer choice

Hope this is clear
Cheers
J
Re: In a certain game played with red chips and blue chips, each   [#permalink] 26 Mar 2014, 07:46
    Similar topics Author Replies Last post
Similar
Topics:
4 Experts publish their posts in the topic A box contains only red chips, white chips, and blue chips. Walkabout 3 14 Dec 2012, 04:19
Experts publish their posts in the topic A box contains only red, white and blue chips. If a chip is Fijisurf 5 15 Dec 2010, 08:11
10 Experts publish their posts in the topic Each of the 25 balls in a certain box is either red, blue, changhiskhan 4 26 Mar 2010, 14:14
3 Experts publish their posts in the topic Each of the 25 balls in a certain box is either red, blue above720 15 11 Dec 2008, 07:03
62 Experts publish their posts in the topic Each of the 25 balls in a certain box is either red, blue or lexis 29 01 May 2008, 10:01
Display posts from previous: Sort by

In a certain game played with red chips and blue chips, each

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.