ruhi160184 wrote:

ninomoi wrote:

ruhi160184 wrote:

C.. 6!*2

Can u pls explain?

They can occupy the 7 seats in the following manner:

123456 or

234567 ( since the aisle seat always needs to get ocupied)

Hence, this can be done in 6! ways.. since we are considering two possibilities, its 6!*2 OR 6!+6!

You and gayathri have the same result, but I believe you each

interpreted the problem differently.

"One of them needs to sit in a seat along the aisle. "

I and gayathri interpreted this statement as there is

one particular person who must sit in one of the two aisle

seats. After that one person is assigned to an aisle seat,

there are 6 seats left for the 5 people. This interpretation

puts all six people in the row, but allows for an empty

seat between two of the friends (in other words, both

aisle seats can be occupied).

Unless I misunderstood your explanation, you are assuming that

there can be no empty seat between the friends occupying

the aisle and that any one of the six friends may be the

one on the aisle. These assumptions offset each other and

produce the same value of 1440.