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# In a certain pond, 50 fish were caught, tagged, and returned

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In a certain pond, 50 fish were caught, tagged, and returned [#permalink]  18 Aug 2011, 10:50
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In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?

(A) 400
(B) 625
(C) 1,250
(D) 2,500
(E) 10,000
[Reveal] Spoiler: OA

Last edited by Bunuel on 24 Nov 2012, 04:04, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Fish - World Problem!! [#permalink]  18 Aug 2011, 10:56
DeeptiM wrote:
In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
(A) 400
(B) 625
(C) 1,250
(D) 2,500
(E) 10,000

2/50 re-caught means that 50 fish represents 1/25th of all fish in the pond. 50*25 = 1250, C
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Re: Fish - World Problem!! [#permalink]  18 Aug 2011, 11:57
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total fish = x
percentage of second catch = (2/50)*100 = 4%
so, x * 4% = 50
x = 1250 ans.
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Re: Fish - World Problem!! [#permalink]  23 Nov 2012, 22:38
so, x * 4% = 50

This is how I solved too.. This works but I dont think this is right...
4% is actually equal to percent of tagged fish in the pond..

Could somebody please confirm if this is right?
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Re: Fish - World Problem!! [#permalink]  24 Nov 2012, 02:28
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Sachin9 wrote:
so, x * 4% = 50

This is how I solved too.. This works but I dont think this is right...
4% is actually equal to percent of tagged fish in the pond..

Could somebody please confirm if this is right?

This is correct.
You are assuming that the total number of fish in the pond is x

4% of x = 50 (Number of tagged fish is 4% of the total fish)
You get x = 1250

So total fish in the pond = 1250
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews GMAT Club Legend Joined: 09 Sep 2013 Posts: 7276 Followers: 384 Kudos [?]: 93 [0], given: 0 Re: In a certain pond, 50 fish were caught, tagged, and returned [#permalink] 09 Dec 2013, 16:48 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ GMAT Club Legend Joined: 09 Sep 2013 Posts: 7276 Followers: 384 Kudos [?]: 93 [0], given: 0 Re: In a certain pond, 50 fish were caught, tagged, and returned [#permalink] 25 Mar 2015, 09:15 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ Intern Joined: 17 Aug 2015 Posts: 3 Followers: 0 Kudos [?]: 0 [0], given: 1 In a certain pond, 50 fish were caught, tagged, and returned [#permalink] 01 Oct 2015, 11:35 VeritasPrepKarishma wrote: Sachin9 wrote: so, x * 4% = 50 This is how I solved too.. This works but I dont think this is right... 4% is actually equal to percent of tagged fish in the pond.. Could somebody please confirm if this is right? This is correct. You are assuming that the total number of fish in the pond is x 4% of x = 50 (Number of tagged fish is 4% of the total fish) You get x = 1250 So total fish in the pond = 1250 Why is the total number of tagged fish 50 as opposed to 98. I got 98 by adding the number of tagged fish in the first catch and the number of tagged fish in the second catch. -> 50+48 = 98 EMPOWERgmat Instructor Status: GMAT Assassin/Co-Founder Affiliations: EMPOWERgmat Joined: 19 Dec 2014 Posts: 4594 Location: United States (CA) GMAT 1: 800 Q51 V49 GRE 1: 340 Q170 V170 Followers: 193 Kudos [?]: 1275 [1] , given: 136 Re: In a certain pond, 50 fish were caught, tagged, and returned [#permalink] 01 Oct 2015, 15:28 1 This post received KUDOS Expert's post HI tinnyshenoy, This prompt is about ratios (and in the broader sense, it's an example of 'representative sampling'). To start, we're told that 50 fish are caught, tagged and returned to the pond. There are now an UNKNOWN number of total fish in the pond, but 50 of them are 'tagged.' Later on, 50 fish are again caught, but 2 of them are ALREADY TAGGED. We're told that the percent of fish IN THIS GROUP that are tagged is approximately = the TOTAL percent of ALL fish that are tagged....With this information, we can set up a ratio... 2/50 = ratio of tagged fish in this sample 50/X = ratio of tagged fish in the pond 2/50 = 50/X Now we can cross-multiply and solve for X... 2X = 2500 X = 1250 Final Answer: [Reveal] Spoiler: C GMAT assassins aren't born, they're made, Rich _________________ Rich Cohen Rich.C@empowergmat.com EMPOWERgmat Online Course | GMAT Club Verified Reviews for EMPOWERgmat & Special Discount http://www.empowergmat.com Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 6062 Location: Pune, India Followers: 1596 Kudos [?]: 8934 [1] , given: 195 Re: In a certain pond, 50 fish were caught, tagged, and returned [#permalink] 01 Oct 2015, 18:49 1 This post received KUDOS Expert's post tinnyshenoy wrote: VeritasPrepKarishma wrote: Sachin9 wrote: so, x * 4% = 50 This is how I solved too.. This works but I dont think this is right... 4% is actually equal to percent of tagged fish in the pond.. Could somebody please confirm if this is right? This is correct. You are assuming that the total number of fish in the pond is x 4% of x = 50 (Number of tagged fish is 4% of the total fish) You get x = 1250 So total fish in the pond = 1250 Why is the total number of tagged fish 50 as opposed to 98. I got 98 by adding the number of tagged fish in the first catch and the number of tagged fish in the second catch. -> 50+48 = 98 Very simply - the 50 fish caught in the second catch were not tagged. They were just caught and it was observed that 2 of them are tagged. The leftover 48 were not tagged. The second catch was only to find the approximate percentage of tagged fish in the pond (a technique called sampling). For example: In a large population, it is difficult to find the number of people with a certain trait, say red hair. So you pick up 100 people at random (unbiased selection) and see the number of people who have red hair. Say, 12 have red hair. So you can generalise that approximately 12% of the whole population has red hair. Here, since counting the number of total fish in the pond is hard, they tagged 50 and let them disperse evenly in the population. Then they caught 50 and found 2 to be tagged. So approximately 4% of the fish were tagged. So 50 is 4% of the entire fish population of the pond. Note that the method uses huge approximation because of the small sample number. If 1 more tagged fish were caught among the 50, it would change the approximated fish population number by a huge amount. But they have given us that "the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond" so we can make this approximation. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: In a certain pond, 50 fish were caught, tagged, and returned   [#permalink] 01 Oct 2015, 18:49
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