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# In a certain senior class, 72 percent of the male students

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Manager
Joined: 30 Jan 2006
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In a certain senior class, 72 percent of the male students [#permalink]  15 Apr 2006, 13:35
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In a certain senior class, 72 percent of the male students and 80 percent of the female students have applied to college. What fraction of the students in the senior class are male?

1) There are 840 students in the senior class.

2) 75 percent of the students in the senior class have applied to college.

Manager
Joined: 09 Feb 2006
Posts: 129
Location: New York, NY
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Statement 1 -- this is insufficient, because we do not know anything about the percentage breakouts of males or females, or of those who applied to college.

Statement 2: Sufficient. Let m = number of males, and f = number of femals. m+f = T (total student body). We can set up an equation for the perccentage of people who applied to college. (.72m + .8f)/T = .75

.75m + .75f = .72m + .8f
.03m = .05f

The ratio of males to females in this group is given by m/f = 5/3

Now we can find out the fraction of males represented in the total student body, because we know m + f = T. f = 3/5m, so m + 3/5m = T.

8/5m = t

m = 5/8 t

Therefore, males represent 5/8 of the student body.
Senior Manager
Joined: 11 Nov 2005
Posts: 328
Location: London
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Agree B.

good explanation jcgoodchild.

jcgoodchild wrote:

Statement 1 -- this is insufficient, because we do not know anything about the percentage breakouts of males or females, or of those who applied to college.

Statement 2: Sufficient. Let m = number of males, and f = number of femals. m+f = T (total student body). We can set up an equation for the perccentage of people who applied to college. (.72m + .8f)/T = .75

.75m + .75f = .72m + .8f
.03m = .05f

The ratio of males to females in this group is given by m/f = 5/3

Now we can find out the fraction of males represented in the total student body, because we know m + f = T. f = 3/5m, so m + 3/5m = T.

8/5m = t

m = 5/8 t

Therefore, males represent 5/8 of the student body.
Manager
Joined: 30 Jan 2006
Posts: 146
Followers: 1

Kudos [?]: 10 [0], given: 0

jcgoodchild wrote:

Statement 1 -- this is insufficient, because we do not know anything about the percentage breakouts of males or females, or of those who applied to college.

Statement 2: Sufficient. Let m = number of males, and f = number of femals. m+f = T (total student body). We can set up an equation for the perccentage of people who applied to college. (.72m + .8f)/T = .75

.75m + .75f = .72m + .8f
.03m = .05f

The ratio of males to females in this group is given by m/f = 5/3

Now we can find out the fraction of males represented in the total student body, because we know m + f = T. f = 3/5m, so m + 3/5m = T.

8/5m = t

m = 5/8 t

Therefore, males represent 5/8 of the student body.

Makes complete sense now! Thanks

OA is B.
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