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In a certain senior class, 75 percent of the male students [#permalink]

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08 Apr 2006, 09:50

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In a certain senior class, 75 percent of the male students and 80 percent of the female students have applied to college. What fraction of the students in the senior class are male?

1. There are 840 students in the senior class
2. 75 percent of the students in the senior class have applied to college

I just got this same question in GMATPrep. I put E. We need to know the percentage of students that are male to answer this question (at least that's what I thought), but we don't. The OA is B, but that made no sense to me.

I just got this same question in GMATPrep. I put E. We need to know the percentage of students that are male to answer this question (at least that's what I thought), but we don't. The OA is B, but that made no sense to me.

jcgoodchild,

trick here is its asking ratio of number male students to total number of students. So we don't need A because we can replace female students by total students - Male students.

GMAT_Crack -- I realized what the question is asking. I had written out a whole post explaining the issue when I think I stumbled on the answer.

Ok, so we want to find the percentage of students who are male. We know a couple of things. 72% of males applied to college and 80% of females applied to college, and from B we know that this is equal to 75% of the student body.

(.72m + .8f) / (m+f) = .75

To your point, they want the ratio of male to femal students.

.72m + .8f = .75m + .75f
.05f = .03m

m/f = .05/.03 = 5/3

So the fraction of male students is 5/8 ths. Sound right?

GMAT_Crack -- I realized what the question is asking. I had written out a whole post explaining the issue when I think I stumbled on the answer.

Ok, so we want to find the percentage of students who are male. We know a couple of things. 72% of males applied to college and 80% of females applied to college, and from B we know that this is equal to 75% of the student body.

(.72m + .8f) / (m+f) = .75

To your point, they want the ratio of male to femal students.

.72m + .8f = .75m + .75f .05f = .03m

m/f = .05/.03 = 5/3

So the fraction of male students is 5/8 ths. Sound right?

If you use .75 as given in the question instead of .72 you won't get a ratio!!

GMAT_Crack -- I realized what the question is asking. I had written out a whole post explaining the issue when I think I stumbled on the answer.

Ok, so we want to find the percentage of students who are male. We know a couple of things. 72% of males applied to college and 80% of females applied to college, and from B we know that this is equal to 75% of the student body.

(.72m + .8f) / (m+f) = .75

To your point, they want the ratio of male to femal students.

.72m + .8f = .75m + .75f .05f = .03m

m/f = .05/.03 = 5/3

So the fraction of male students is 5/8 ths. Sound right?

Hey dude,
You are calculating the ratio of m/f, but we need here m/T where T is the total number of students.
so T = m + f
--> f = T-m
Now in equation in blue, replace f = t-m

GMAT_Crack -- I realized what the question is asking. I had written out a whole post explaining the issue when I think I stumbled on the answer.

Ok, so we want to find the percentage of students who are male. We know a couple of things. 72% of males applied to college and 80% of females applied to college, and from B we know that this is equal to 75% of the student body.

(.72m + .8f) / (m+f) = .75

To your point, they want the ratio of male to femal students.

.72m + .8f = .75m + .75f .05f = .03m

m/f = .05/.03 = 5/3

So the fraction of male students is 5/8 ths. Sound right?

Hey dude, You are calculating the ratio of m/f, but we need here m/T where T is the total number of students. so T = m + f --> f = T-m Now in equation in blue, replace f = t-m

------> [ .72m + .8(T-m)] / T = .75

from this we need to get m/T.

---------> .8 - .08*m/T = .75

---------> .05 = .08*m/T ---> m/T = 5/8

Hope this will help everyone.

It is not .72 it is .75 and you cannot deduce the fraction if you follow that equation

Last edited by jodeci on 08 Apr 2006, 22:16, edited 1 time in total.

I keep getting m/t = 1, which makes little sense to me. It seems that everyone is getting this ratio too. Perhaps this is truly the answer. I've been scouring my calculation for mistakes but everything I have down is logical. I don't think there are any females in this school....

I've tried it through formulas and charts. Everything points to 0 females and all males. Hell, you can even use the 1st statement they give you and try it out with that. It'll give you 840 males.

In a certain senior class, 75 percent of the male students and 80 percent of the female students have applied to college. What fraction of the students in the senior class are male?

1. There are 840 students in the senior class 2. 75 percent of the students in the senior class have applied to college

the question seems poorly structured for me because if there are male and female, both, students in the college, 75 percent of the male students and 80 percent of the female comprise more than 75% of total.

but if 75 percent of the male students and 80 percent of the female comprise more than 75% of total, then thre are only male students. so the fraction of male student is 1 (or 100%).

lets suppose total = 100
male = x
0.75x + 0.8(100-x) = 75
0.75x + 80 -0.8x = 75
0.75x -0.8x = 75-80
0.05x = 5
x = 100

hehe this problem sucks the only reason i would think C is because i kept getting 0 females ... oh well hope i dont get something this silly on my test