In a certain state, gasoline stations compute the price per : GMAT Problem Solving (PS)
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# In a certain state, gasoline stations compute the price per

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15 Apr 2008, 14:21
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73% (01:58) correct 27% (01:51) wrong based on 183 sessions

In a certain state, gasoline stations compute the price per gallon "p", in dollars, charged at the pump by adding a 4 percent sales tax to the dealer's price per gallon "d", in dollars, and then adding a gasoline tax of $0.18 per gallon. Which of the following gives the dealer's price per gallon "d" in terms of the price per gallon "p" charged at the pump? A. d=p-0.22 B. d=p/1.22 C. d=p/1.04 - 0.18 D. d= p-0.18/1.04 E. d = p-0.04/1.18 OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-certain-state-gasoline-stations-compute-the-price-per-100598.html#p776714 [Reveal] Spoiler: OA Last edited by Bunuel on 10 Dec 2013, 05:28, edited 1 time in total. Edited the question and added the OA. Current Student Joined: 27 Mar 2008 Posts: 416 Schools: Kellogg Class of 2011 Followers: 3 Kudos [?]: 43 [1] , given: 1 Re: GMATPrep PS: Can you solve it fast somehow? [#permalink] ### Show Tags 15 Apr 2008, 14:29 1 This post received KUDOS 1 This post was BOOKMARKED p = d*1.04 + 18 (Based on the question. 4% Sales Tax +0.18 cents per gallon) Rearranging, d = (p-0.18)/1.04 Answer is D Manager Joined: 12 Jan 2013 Posts: 244 Followers: 4 Kudos [?]: 69 [0], given: 47 Re: GMATPrep PS: Can you solve it fast somehow? [#permalink] ### Show Tags 10 Dec 2013, 05:24 yellowjacket wrote: p = d*1.04 + 18 (Based on the question. 4% Sales Tax +0.18 cents per gallon) Rearranging, d = (p-0.18)/1.04 Answer is D How is the bolded part even true? Doesn't the question really say: p/gallon = d*1.04 + 18/gallon Thus, how can you "remove" the fractions p/gallon and 1/gallon from both sides without multiplying gallon with d*1.04? What am I missing? Because I easily understand the question when it is done as you say, but logically I just cannot seem to understand WHY the fraction /gallon is not included in your equation. Math Expert Joined: 02 Sep 2009 Posts: 36531 Followers: 7071 Kudos [?]: 92970 [0], given: 10541 Re: GMATPrep PS: Can you solve it fast somehow? [#permalink] ### Show Tags 10 Dec 2013, 05:28 Expert's post 2 This post was BOOKMARKED aeglorre wrote: yellowjacket wrote: p = d*1.04 + 18 (Based on the question. 4% Sales Tax +0.18 cents per gallon) Rearranging, d = (p-0.18)/1.04 Answer is D How is the bolded part even true? Doesn't the question really say: p/gallon = d*1.04 + 18/gallon Thus, how can you "remove" the fractions p/gallon and 1/gallon from both sides without multiplying gallon with d*1.04? What am I missing? Because I easily understand the question when it is done as you say, but logically I just cannot seem to understand WHY the fraction /gallon is not included in your equation. In a certain state, gasoline stations compute the price per gallon "p", in dollars, charged at the pump by adding a 4 percent sales tax to the dealer's price per gallon "d", in dollars, and then adding a gasoline tax of$0.18 per gallon. Which of the following gives the dealer's price per gallon "d" in terms of the price per gallon "p" charged at the pump?

A. d=p-0.22
B. d=p/1.22
C. d=p/1.04 - 0.18
D. d= p-0.18/1.04
E. d = p-0.04/1.18

Price per gallon $$p$$ equals to $$d+0.04d$$ (dealer's price $$d$$ plus 4%) plus $$0.18$$, so $$p=d+0.04d+0.18$$ --> $$p=1.04d+0.18$$ --> $$d=\frac{p-0.18}{1.04}$$.

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-certain-state-gasoline-stations-compute-the-price-per-100598.html#p776714
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Re: GMATPrep PS: Can you solve it fast somehow?   [#permalink] 10 Dec 2013, 05:28
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