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Re: In a clothing store, there are six different colored neckties (red, or [#permalink]
In a clothing store, there are six different colored neckties (red, orange, yellow, green, blue, and indigo) and six different colored shirts (red, orange, yellow, green, blue, and indigo) that must be packed into boxes for gifts. If each box can only fit one necktie and one shirt, what is the probability that all of the boxes will contain a necktie and a shirt of the same color?

A. 719/720
B. 1/120
C. 2/233
D. 3/543
E. 1/720

Total probability is 6! = 720

Now the answer choices are interesting here. Only the options A and E have denominator 720. The option B has 120 so we can hold on to this option for now. Option A has probability of 719/720 which is high and less probably answer choice. We can eliminate options C and D based the denominator. We are left with option B and E.

Of the remaining options , only one box will have shirt and tie in same color.

Ans: E
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Re: In a clothing store, there are six different colored neckties (red, or [#permalink]
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Bunuel wrote:
In a clothing store, there are six different colored neckties (red, orange, yellow, green, blue, and indigo) and six different colored shirts (red, orange, yellow, green, blue, and indigo) that must be packed into boxes for gifts. If each box can only fit one necktie and one shirt, what is the probability that all of the boxes will contain a necktie and a shirt of the same color?

A. 719/720
B. 1/120
C. 2/233
D. 3/543
E. 1/720


For the red necktie, there is a 1/6 chance it will be packed with the red shirt. Given that the reds have been packed together, for the orange necktie, there is a 1/5 chance it will be packed with the orange shirt. Given that the oranges have been packed together, for the yellow necktie, there is a 1/4 chance it will be packed with the yellow shirt. From this point, we see that there is a 1/3 chance the green necktie and shirt will be packed together, a 1/2 chance the blue necktie and shirt will be packed together and, finally, a 1/1 chance the indigo necktie and shirt will be packed together. Therefore, the overall probability is 1/6 x 1/5 x 1/4 x 1/3 x 1/2 x 1/1 = 1/6! = 1/720.

Answer: E
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Re: In a clothing store, there are six different colored neckties (red, or [#permalink]
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Bunuel wrote:
In a clothing store, there are six different colored neckties (red, orange, yellow, green, blue, and indigo) and six different colored shirts (red, orange, yellow, green, blue, and indigo) that must be packed into boxes for gifts. If each box can only fit one necktie and one shirt, what is the probability that all of the boxes will contain a necktie and a shirt of the same color?

A. 719/720
B. 1/120
C. 2/233
D. 3/543
E. 1/720


Once the six shirts have been distributed among 6 boxes, one shirt per box:

P(the first box receives its matching tie) = 1/6 (Of the 6 ties, only 1 is a match.)
P(the next box receives its matching tie) = 1/5 (Of the 5 remaining ties, only 1 is a match.)
P(the next box receives its matching tie) = 1/4 (Of the 4 remaining ties, only 1 is a match.)
P(the next box receives its matching tie) = 1/3 (Of the 3 remaining ties, only 1 is a match.)
P(the next box receives its matching tie) = 1/2 (Of the 2 remaining ties, only 1 is a match.)
P(the next box receives its matching tie) = 1/1 (The 1 remaining tie must be a match.)
To combine these probabilities, we multiply:
1/6 * 1/5 * 1/4 * 1/3 * 1/2 * 1/1 = 1/720

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Re: In a clothing store, there are six different colored neckties (red, or [#permalink]
Conceptual approach:

https://ibb.co/MBRBNL5
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Re: In a clothing store, there are six different colored neckties (red, or [#permalink]
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Probability = Favorable/Total

Total = 6C1 * 6C1
Favorable = 6C1 * 1C1

P = 6C1*1C1/6C1*6C1 = 6!/6!*6! = 1/6! = 1/720 (E)
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Re: In a clothing store, there are six different colored neckties (red, or [#permalink]
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Re: In a clothing store, there are six different colored neckties (red, or [#permalink]
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