In a consumer survey, 85% of those surveyed liked at least : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 24 Jan 2017, 11:29

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In a consumer survey, 85% of those surveyed liked at least

Author Message
Intern
Joined: 19 May 2004
Posts: 7
Location: Denver, CO
Followers: 0

Kudos [?]: 1 [0], given: 0

In a consumer survey, 85% of those surveyed liked at least [#permalink]

### Show Tags

19 May 2004, 14:10
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In a consumer survey, 85% of those surveyed liked at least one of three products: 1,2 and 3. 50% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 5% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?

A) 5
B)10
C)15
D)20
E)25

Does anyone have a good formula to use when there are more than two possible combinations of overlap?
SVP
Joined: 30 Oct 2003
Posts: 1793
Location: NewJersey USA
Followers: 6

Kudos [?]: 98 [0], given: 0

### Show Tags

19 May 2004, 18:53
Hi,

There is a formula but this problem cannot be solved using that formula.

Here is my solution.

Let products be X,Y,Z
From the stem we know that x+y+z+xy+xz+yz+xyz = 85
So x+y+z+xy+xz+yz = 85-xyz = 80 because xyz=5

X = x + xy + xz + xyz = 50 hence
x + xy + xz = 45
Similarly
y + xy + yz = 30-5 = 25
z + xz + yz = 20-5 = 15

x+y+z+xy+xz+yz = 85
= 80+xy+xz+yz = 85
Hence xy+xz+yz = 5

No of people who like more than one product
= xy+xz+yz +xyz = 5+5 = 10

Senior Manager
Joined: 02 Mar 2004
Posts: 327
Location: There
Followers: 1

Kudos [?]: 0 [0], given: 0

Re: Need help with PS question [#permalink]

### Show Tags

19 May 2004, 20:12
Given |A| = 50
|B| = 30
|C| = 20
|ABC| = 5
|AUBUC| = 85

Find |AUB|+|BUC|+|AUC|-2|ABC|

|AUBUC| = |A|+|B|+|C|-|AUB|-|BUC|-|CUA|+|ABC|

Manager
Joined: 10 Mar 2004
Posts: 64
Location: Dallas,TX
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

20 May 2004, 11:47
i think making a Venn Diagram for this will be simpler. I find it that way to be simpler. Answer remains the same.

cheers
Manager
Joined: 27 Feb 2004
Posts: 185
Location: illinois
Followers: 1

Kudos [?]: 26 [0], given: 0

### Show Tags

20 May 2004, 12:44
As an extension to the above problem....

How many people(or %) of people Liked ONLY 1 but NOT 2 and NOT 3...

How can we modify the formula then...

Halle How did you get 2AB...Please clarify...
20 May 2004, 12:44
Display posts from previous: Sort by