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In a cookie-eating contest, there are 200 cookies provided

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In a cookie-eating contest, there are 200 cookies provided [#permalink] New post 18 Jun 2011, 20:03
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In a cookie-eating contest, there are 200 cookies provided to each contestant. Both start at the same time. Contestant A wins the contest by eating 20 more cookies than Contestant B. How many cookies did the winner eat altogether?

(1) Contestant A ate his cookies at a constant rate of 20 cookies per minute and Contestant B ate her cookies at a constant rate of 15 cookies per minute.

(2) Contestant A is younger than Contestant B.
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Re: Good D.S Problem [#permalink] New post 18 Jun 2011, 22:23
guygmat wrote:
In a cookie-eating contest, there are 200 cookies provided to each contestant. Both start at the same time. Contestant A wins the contest by eating 20 more cookies than Contestant B. How many cookies did the winner eat altogether?

(1) Contestant A ate his cookies at a constant rate of 20 cookies per minute and Contestant B ate her cookies at a constant rate of 15 cookies per minute.

(2) Contestant A is younger than Contestant B.



Answer A
st:1
20X-15X = 20
5X= 20
X = 4
so the winner ate 20*4 = 80 cookies
hence sufficient

st:2 irrelevant
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Re: Good D.S Problem [#permalink] New post 19 Jun 2011, 01:54
Stmt1:
Rate of A=20 cookies/min
Rate of B=15 cookies/min
So in 1 min A can eat 5 more cookies than B.

Given that A has eaten 20 more cookies than B.
A can eat 5 more cookies than B in 1 min
A can eat 20 more cookies than B in 4 min

Hence total number of cookies that A ate: 20(rate of A) * 4 (time) = 80 cookies. Sufficient.

Stmt2: Irrelevant.

OA A.
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Re: Good D.S Problem [#permalink] New post 23 Jun 2011, 03:26
a 20t-15t = 20

t = 4 mint. thus 20*4 = 80 cookies.

A it is.
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Re: Good D.S Problem [#permalink] New post 24 Jun 2011, 02:01
A is sufficient
Let t be time taken ,a and b be cookies eaten by each participant
20t-15t = a-b=20
t=4 mins
hence a the winner eats 4*20 = 80 cookies
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Re: Good D.S Problem [#permalink] New post 06 Sep 2011, 02:24
Quote:
In a cookie-eating contest, there are 200 cookies provided to each contestant. Both start at the same time. Contestant A wins the contest by eating 20 more cookies than Contestant B. How many cookies did the winner eat altogether?

(1) Contestant A ate his cookies at a constant rate of 20 cookies per minute and Contestant B ate her cookies at a constant rate of 15 cookies per minute.

(2) Contestant A is younger than Contestant B.


From Statement 1
Work/Speed=Time
A: 20/min
B:15/min
We have the rate of each contestant, total number of cookies and differential no. of cookies eaten.
We have every info needed to find out total number of cookies eaten by A.
---> Sufficient


From Statement 2
Not helpful. Insufficient.

this is how it will work out if you pursue the solution from statement 1...
Speed*Time=Work
speed*time of A - speed*time of B = Difference in no. of cookies eaten
Let t=time taken for contest
20t-15t=20
5t=20
t=4

20*4=80cookies
A ate 80 cookies.

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Re: Good D.S Problem [#permalink] New post 29 Sep 2011, 20:05
guygmat wrote:
In a cookie-eating contest, there are 200 cookies provided to each contestant. Both start at the same time. Contestant A wins the contest by eating 20 more cookies than Contestant B. How many cookies did the winner eat altogether?

(1) Contestant A ate his cookies at a constant rate of 20 cookies per minute and Contestant B ate her cookies at a constant rate of 15 cookies per minute.

(2) Contestant A is younger than Contestant B.


Good question. kudos....
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Re: Good D.S Problem [#permalink] New post 01 Oct 2011, 00:02
guygmat wrote:
In a cookie-eating contest, there are 200 cookies provided to each contestant. Both start at the same time. Contestant A wins the contest by eating 20 more cookies than Contestant B. How many cookies did the winner eat altogether?

(1) Contestant A ate his cookies at a constant rate of 20 cookies per minute and Contestant B ate her cookies at a constant rate of 15 cookies per minute.

(2) Contestant A is younger than Contestant B.


Total number of cookies = 200. This is irrelevant information because A and B did not finish all the cookies.
A - B = 20
A = total cookies eaten by A
B = total cookies eaten by B

(1) A = 20t
B =15t
20t - 15t = 20 => t = 4
A = 20x4 = 80
Sufficient

(2) Not Sufficient

(A) is the answer.
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Re: Good D.S Problem   [#permalink] 01 Oct 2011, 00:02
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