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In a grocery store, the average sale for month X was A

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In a grocery store, the average sale for month X was A [#permalink] New post 22 Mar 2005, 07:13
00:00
A
B
C
D
E

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(N/A)

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100% (01:54) correct 0% (00:00) wrong based on 1 sessions
In a grocery store, the average sale for month X was A dollars. Was the average sale for month Y at least 20 percent higher than that for month X?

(1) For month X, total revenue from sales was $ 35,000

(2) For month Y, total revenue fro sales was $ 60,000
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 [#permalink] New post 22 Mar 2005, 08:37
This looks like C.

Anyone wants to try a variation?

Total revenues in Y = $40,000.

[Everything else remains the same]
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 [#permalink] New post 22 Mar 2005, 08:51
If "the average sale for month X" implies, average daily sales for month X, I would go with (E).

Month X could have any of 31, 30, 28 or 29 days.

Since the avegare daily sales = A, the total sales for Month X could be any of: 31X, 30X, 28X or 29X

Now, month Y could have any of 31, 30, 28 or 29 days in all.

Clearly, statements (1) and (2) are insufficient if treated separately, let us just examine case (C) here:

For month X, total revenue from sales was $ 35,000 - (1)
AND
For month Y, total revenue fro sales was $ 60,000 - (2)

(1) implies, the average daily sales for Month X could be
- $35000/31 or
- $35000/30 or
- $35000/29 or
- $35000/28

(2) average daily sales for Month Y could be
- $60000/31 or
- $60000/30 or
- $60000/29 or
- $60000/28

Hence, both combined, insufficient.

Is my approach fine or am I just being paranoid? :)
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 [#permalink] New post 22 Mar 2005, 10:00
EDITED:

"C" ....we don't know what type of month we are talking about but for any combination of avg X/28,X/29,X/30,X/31 ( min avg will be when X/31 and max for X/28) same for Y.....we can calculate that in all cases avg (u can only calcualte min and max avg) of Y is always > than 20% X....so suff....I guess if Y was 40,000 then it will be E, altho I haven't calculated it.

Last edited by banerjeea_98 on 22 Mar 2005, 11:11, edited 1 time in total.
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 [#permalink] New post 22 Mar 2005, 11:09
hmmm could be E dunno about the number of days..
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 [#permalink] New post 22 Mar 2005, 16:04
Questions that seem straight would have tough solutions

I would go for E
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 [#permalink] New post 22 Mar 2005, 18:12
'C'

For all combinations (month --> 28,29,30,31) month Y avg is 20% greater than month X avg
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Re: DS- Average sale [#permalink] New post 29 Mar 2005, 10:25
swath20 wrote:
In a grocery store, the average sale for month X was A dollars. Was the average sale for month Y at least 20 percent higher than that for month X?

(1) For month X, total revenue from sales was $ 35,000

(2) For month Y, total revenue fro sales was $ 60,000


I selected E
you need to know the number of transactions for each month to compute the average sale value.

What's the OA?
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 [#permalink] New post 29 Mar 2005, 11:18
I think the ans is C.
If the question stem didn’t ask for “at leastâ€
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 [#permalink] New post 31 Mar 2005, 11:04
Dont have the OE but the OA is E
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 [#permalink] New post 31 Mar 2005, 11:37
Explanation for choose E might be because "average sales" is undefined in the question. You guys added the word "daily" to make it clear, but is it the intend of the question?
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 [#permalink] New post 01 Apr 2005, 08:58
ywilfred wrote:
maaverick wrote:
If "the average sale for month X" implies, average daily sales for month X, I would go with (E).

Month X could have any of 31, 30, 28 or 29 days.

Since the avegare daily sales = A, the total sales for Month X could be any of: 31X, 30X, 28X or 29X

Now, month Y could have any of 31, 30, 28 or 29 days in all.

Clearly, statements (1) and (2) are insufficient if treated separately, let us just examine case (C) here:

For month X, total revenue from sales was $ 35,000 - (1)
AND
For month Y, total revenue fro sales was $ 60,000 - (2)

(1) implies, the average daily sales for Month X could be
- $35000/31 or
- $35000/30 or
- $35000/29 or
- $35000/28

(2) average daily sales for Month Y could be
- $60000/31 or
- $60000/30 or
- $60000/29 or
- $60000/28

Hence, both combined, insufficient.

Is my approach fine or am I just being paranoid? :)


Good explanation.


Good thinking but will this not lead to answer E, for if you calculate them out you'll see the answer is unique and C would be your answer.
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keep on seeking, and you will find;
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  [#permalink] 01 Apr 2005, 08:58
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