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In a particular machine, there are 2 gears that interlock [#permalink]

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16 Aug 2012, 07:32

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In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for atleast 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear.

(1) The diameter of the larger gear is twice the diameter of smaller gear. (2) The smaller gear revolves 600 times per minute.

Please put your reasoning across and then I will ask my doubt. I want to see if I am assuming much in this question.

Re: In a particular machine, there are 2 gears [#permalink]

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16 Aug 2012, 09:32

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imhimanshu wrote:

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for atleast 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear.

a) the diameter of the larger gear is twice the diameter of smaller gear. b) The smaller gear revolves 600 times per minute.

Please put your reasoning across and then I will ask my doubt. I want to see if I am assuming much in this question.

Thanks

(1) We can deduce that the smaller gear makes two rotations while the larger gear makes just one rotation. No information about the speed of revolution, so we cannot establish any connection with time. Not sufficient.

(2) No information about the larger gear. Not sufficient.

(1) and (2): The larger gear makes 300 rotations per minute and the smaller gear 600 per minute. So, we can calculate how long it takes in minutes each one to do 6,000,000,000 rotations, take the difference and convert to days...really messy. But being a DS question, you shouldn't spend time on working out the final answer.

Choose Answer C, and move on.
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Re: In a particular machine, there are 2 gears [#permalink]

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16 Aug 2012, 19:33

Eva above is pretty much spot-on. Note that the larger gear having a diameter twice as long as the smaller gear's means that the larger will turn once for every 4 times the smaller does, but the logical process remains sound. Do also note that as Eva mentioned, you should not bother working out the "complete" answer to the question; once you figure out that you need both the ratio of circumferences (or diameters/radii) and the turn speed of one gear, you can answer the question.

Re: In a particular machine, there are 2 gears [#permalink]

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17 Aug 2012, 03:33

DonQuixote wrote:

Eva above is pretty much spot-on. Note that the larger gear having a diameter twice as long as the smaller gear's means that the larger will turn once for every 4 times the smaller does, but the logical process remains sound. Do also note that as Eva mentioned, you should not bother working out the "complete" answer to the question; once you figure out that you need both the ratio of circumferences (or diameters/radii) and the turn speed of one gear, you can answer the question.

Why 4 times? Circumference of the circle is \(\pi*{Diameter}\). So, if one of the diameters is twice the other one, circumference is also twice, which means twice more rotations for the smaller gear. No?
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Re: In a particular machine, there are 2 gears that interlock [#permalink]

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17 Aug 2012, 16:16

+1 C

Beautiful question. When the small gear rotates one time, the big gear rotates 1/2 its diameter. Therefore, the big gear rotates 300 times in 1 minute. With that information, we can calculate the time for both gears when they make 6 x 10^9 times.
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Re: In a particular machine, there are 2 gears that interlock [#permalink]

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17 Aug 2012, 21:16

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Though I also found the answer to be C. However, I want to ask one question.

The question states that each gear will last for atleast 6,000,000,000 revolutions.

What if the bigger gear last for 9,000,000,000 and smaller gear will last for 6,000,000,000 revolution. In this scenario, we may not be having definite scenario. Isn't it. So, the answer must be E

imhimanshu wrote:

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for atleast 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear.

(1) The diameter of the larger gear is twice the diameter of smaller gear. (2) The smaller gear revolves 600 times per minute.

Please put your reasoning across and then I will ask my doubt. I want to see if I am assuming much in this question.

Re: In a particular machine, there are 2 gears that interlock [#permalink]

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17 Aug 2012, 21:26

imhimanshu wrote:

Though I also found the answer to be C. However, I want to ask one question.

The question states that each gear will last for atleast 6,000,000,000 revolutions.

What if the bigger gear last for 9,000,000,000 and smaller gear will last for 6,000,000,000 revolution. In this scenario, we may not be having definite scenario. Isn't it. So, the answer must be E

imhimanshu wrote:

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for atleast 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear.

(1) The diameter of the larger gear is twice the diameter of smaller gear. (2) The smaller gear revolves 600 times per minute.

Please put your reasoning across and then I will ask my doubt. I want to see if I am assuming much in this question.

Thanks

the larger gear is guaranteed to last how many days longer than the smaller gear.

The question is about the guaranteed number of days and not about possible scenarios.
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Re: In a particular machine, there are 2 gears that interlock [#permalink]

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17 Jan 2013, 00:06

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Each gear has life to 6,000,000,000 revolutions. As both gears are interlocked, smaller gear will have more revolutions and will wear out before the larger one.

(1) The diameter of the larger gear is twice the diameter of smaller gear. INSUFFICIENT: This means - the circumference of the larger gear is twice that of smaller gear. I.e. 1 revolution of larger gear = smaller gear rotates two times. Even if we know relative ratio for diameters, we don’t know what rate at they are revolving per minute. - If the gears are rotating at extreme high speed, they will wear out soon -> hence difference of their life (in minutes) will be smaller. - If the gears are rotating at extreme slow speed, they will last lot longer -> hence difference of their life (in minutes) will be much larger. Hence we cannot conclude how many days the gears will last long.

(2) The smaller gear revolves 600 times per minute. INSUFFICIENT: This information is clearly insufficient. This tells the revolution rate only for smaller gear. No info about larger gear (speed or relative diameter ratio)

Combining (1) & (2) SUFFICIENT: As we know smaller gear has 600 RPM and 1/2 the diameter than larger one -> the larger gear rotate at half the speed i.e. 300 RPM and hence we can find out how many days they can last long.

We can stop at this point (no need to calculate further during actual exam) but just for sake of curiosity lets calculate further: No of days larger gear lasts longer than smaller gear = \(\frac{6,000,000,000}{24*60*60 minutes} * (\frac{1}{300}-\frac{1}{600}) = 115.74 days.\)

Re: In a particular machine, there are 2 gears that interlock [#permalink]

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04 Mar 2013, 01:48

imhimanshu wrote:

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for atleast 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear.

(1) The diameter of the larger gear is twice the diameter of smaller gear. (2) The smaller gear revolves 600 times per minute.

Please put your reasoning across and then I will ask my doubt. I want to see if I am assuming much in this question.

Thanks

(1) The diameter of the larger gear is twice the diameter of smaller gear. This means for Bigger gear # of revolution = 6,000,000,000 / pi * 2d Smaller gear # of revolution = 6,000,000,000 / pi * d. But we don't know d (diameter)

(2) The smaller gear revolves 600 times per minute.

this gives rate of smaller gear. Not sufficient. We can find

(6,000,000,000 / pi * d) = 600. We can find d.

1 + 2:

Now, we know diameter of Bigger gear we can find Bigger gear # of revolution per min - Smaller gear # of revolution

Re: In a particular machine, there are 2 gears that interlock [#permalink]

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17 Nov 2014, 13:16

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In a particular machine, there are 2 gears that interlock [#permalink]

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01 Aug 2016, 03:52

imhimanshu wrote:

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for atleast 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear.

(1) The diameter of the larger gear is twice the diameter of smaller gear. (2) The smaller gear revolves 600 times per minute.

Please put your reasoning across and then I will ask my doubt. I want to see if I am assuming much in this question.

Thanks

Given in the stimulus , One gear is bigger than the other. Both gear will work till 6000000 revolution Find the life of the larger gear. Life of gear is a function of revolution they makes. "{They will last till 600000000 revolution-given in the question} Revolution is dependant on the circumference and thus depends on the diameter of the gears. Revolution is also dependant on the rate of revolution of gear per second or per minute or per hour

AIM:-Look out for Radius+Rate info

(1) The diameter of the larger gear is twice the diameter of smaller gear. We got the relative radius info. We don't have exact radius values. And we are still missing rate of revolution INSUFFICIENT

(2) The smaller gear revolves 600 times per minute. Nice:- we got the rate info for smaller one since the smaller one and bigger one are connected so their rate will be same; but this statement doesn't talk about diameter INSUFFICENT

COMBINE we have the radius as well as rate info for both gear

SUFFICIENT

ANSWER IS C
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Re: In a particular machine, there are 2 gears that interlock [#permalink]

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18 Sep 2016, 20:37

imhimanshu wrote:

In a particular machine, there are 2 gears that interlock; One gear is larger in circumference than the other. The manufacturer of the gears guarantees that each gear will last for atleast 6,000,000,000 revolutions. Assuming that there is no slippage between the 2 gears and that when one gear rotates the other gear also rotates, the larger gear is guaranteed to last how many days longer than the smaller gear.

(1) The diameter of the larger gear is twice the diameter of smaller gear. (2) The smaller gear revolves 600 times per minute.

Please put your reasoning across and then I will ask my doubt. I want to see if I am assuming much in this question.

Thanks

Just looking at the question, (2) is clearly insufficient because you don't know how big the large gear is nor it's revolution rate. (1) you can see the relation of the gears' sizes. However, you can't translate these sizes into time. There's no way to calculate the numbers of days needed for either gear to rotate 6000000000 revs so insufficient. With (1+2) you have the relationship between gear sizes and the time for one gear. Therefore, without doing any calculation, it should be C.

In a particular machine, there are 2 gears that interlock [#permalink]

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21 Oct 2016, 11:05

PrashantPonde wrote:

Each gear has life to 6,000,000,000 revolutions. As both gears are interlocked, smaller gear will have more revolutions and will wear out before the larger one.

(1) The diameter of the larger gear is twice the diameter of smaller gear. INSUFFICIENT: This means - the circumference of the larger gear is twice that of smaller gear. I.e. 1 revolution of larger gear = smaller gear rotates two times. Even if we know relative ratio for diameters, we don’t know what rate at they are revolving per minute. - If the gears are rotating at extreme high speed, they will wear out soon -> hence difference of their life (in minutes) will be smaller. - If the gears are rotating at extreme slow speed, they will last lot longer -> hence difference of their life (in minutes) will be much larger. Hence we cannot conclude how many days the gears will last long.

(2) The smaller gear revolves 600 times per minute. INSUFFICIENT: This information is clearly insufficient. This tells the revolution rate only for smaller gear. No info about larger gear (speed or relative diameter ratio)

Combining (1) & (2) SUFFICIENT: As we know smaller gear has 600 RPM and 1/2 the diameter than larger one -> the larger gear rotate at half the speed i.e. 300 RPM and hence we can find out how many days they can last long.

We can stop at this point (no need to calculate further during actual exam) but just for sake of curiosity lets calculate further: No of days larger gear lasts longer than smaller gear = \(\frac{6,000,000,000}{24*60*60 minutes} * (\frac{1}{300}-\frac{1}{600}) = 115.74 days.\)

Hence choice(C) is the answer.

I am getting the below expression. Can anyone confirm. Thanks!

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