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In a sample of college students, 40 percent are third year students an [#permalink]
24 Dec 2005, 20:20

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Difficulty:

35% (medium)

Question Stats:

73% (02:53) correct
27% (01:33) wrong based on 62 sessions

In a sample of college students, 40 percent are third year students and 70 percent are not second-year students. What fraction of those students who are not third-year students are second-year students?

Re: In a sample of college students, 40 percent are third year students an [#permalink]
26 Dec 2005, 00:18

Bhai wrote:

In a sample of college students, 40 percent are third-year students and 70 percent are not second-year students. What fraction of those students who are not third-year students are second-year students? (A) 3/4 (B) 2/3 (C) 4/7 (D) 1/2 (E) 3/7

Let the number of students be 100.

3rd year = 40
First year or 3rd year = 70 => First year = 30
and Second year = 30
Second /First + Second = 30/60 = 1/2

Re: In a sample of college students, 40 percent are third year students an [#permalink]
24 Feb 2015, 11:30

Bhai wrote:

In a sample of college students, 40 percent are third-year students and 70 percent are not second-year students. What fraction of those students who are not third-year students are second-year students? (A) 3/4 (B) 2/3 (C) 4/7 (D) 1/2 (E) 3/7

Hi there! Here is the approach I took:

Third year students: 40% Not Third Year: 60%

Not Second Year: 70% Second Year: 30%

What fraction of those students who are not third-year students are second-year students?

We know those who are not third year are 60% and we know second year students are 30%

Re: In a sample of college students, 40 percent are third year students an [#permalink]
28 Feb 2015, 07:22

Expert's post

Bhai wrote:

In a sample of college students, 40 percent are third year students and 70 percent are not second-year students. What fraction of those students who are not third-year students are second-year students?

(A) 3/4 (B) 2/3 (C) 4/7 (D) 1/2 (E) 3/7

Since we're talking till third year students so we have first year, second year and third year students. Given that T = 40 ----- (I) F + T = 70 ----- (II)

From (I) and (II), F = 30 Hence S = 100 - 40 - 30 = 30

Those who are not third year students = F + S = 30 + 30 = 60 Fraction of second year and those who are not third year students = 30/60 = 1/2 Hence option D

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