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In a stationery store, A costs X dollars, B costs Y dollars,

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In a stationery store, A costs X dollars, B costs Y dollars, [#permalink] New post 24 May 2009, 08:05
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D
E

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In a stationery store, A costs X dollars, B costs Y dollars, if $10 is enough to buy 5 A and 3 B, whether $10 is enough to buy 4A and 4B?
1). A costs less than $1
2). $10 is enough to buy 11 A.
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Re: stationery store [#permalink] New post 28 May 2009, 10:08
Another E.

1st statement

x < 1, let suppose x = 0.2 $ & y = 3 $

10>= 5A + 3B -- given than 5A + 3B = 10 $

But if put same value in 10 >= 4A + 4B , to buy 4 B items itself we need 12$.
So 1st statement does not conclude anything

2nd statement

10 >= 11A => A =< 10/11 ..again same as 1st statement
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Re: stationery store [#permalink] New post 28 May 2009, 19:38
Case 1
Let A be 2 Cents -- 99 Cents
10$ is never sufficient

Case 2
Any Value for A will make 4a+4b greater than 10$

Hence IMO D is the answer
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Re: stationery store [#permalink] New post 28 May 2009, 22:14
E.
None of the statements says anything abt. B. hence insuff. (B can be as low as .000001 cents or can be as high as 3.3)
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Re: stationery store [#permalink] New post 29 May 2009, 07:48
The stem says 5A+3B <= 10
Asked 4A + 4B <= 10
Case:1
Let A = .01$, B--> 3.31............. Not sufficient to Buy 4A + 4B
Let A = .99$, b --> 1.68 .......... Not sufficient to Buy 4A + 4B

Hence Statement 1 is sufficient to say NO

Case: 2
Its the same as Case-1

IMO D

Whats the OA??
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Re: stationery store [#permalink] New post 29 May 2009, 08:22
OA is E .

stat1 &2 mean the same.
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Re: stationery store [#permalink] New post 01 Jun 2009, 07:30
Any value satisfying either case 1 or case 2 will always make 4a+4b greater than 10$
Any explaination supporting OA will be very helpful
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Re: stationery store [#permalink] New post 01 Jun 2009, 14:30
vcbabu wrote:
In a stationery store, A costs X dollars, B costs Y dollars, if $10 is enough to buy 5 A and 3 B, whether $10 is enough to buy 4A and 4B?
1). A costs less than $1
2). $10 is enough to buy 11 A.


given - $10 is enough to buy 5 A and 3 B

5A+3B < 10----(1)

statement 1:
A costs less than $1

suppose A costs 0.99. From equation (1) B comes out to be 1.6 (this is the max possible value for A=0.99 and 5A+3B =9.99 )

for max value of A , 4A+4B > 10 and for min value of A 4A+4B < 10.
statement 1 is INSUFFICIENT.

statement 2:
$10 is enough to buy 11 A.

11A < 10
A < 0.90

From equation (1) B comes out to be 1.8 (this is the max possible value for A=0.9 and 5A+3B =9.99 )
for max value of A , 4A+4B > 10 and for min value of A 4A+4B < 10.

statement 2 is also INSUFFICIENT.

Together they say only that A is less than 1$ or (10 / 11)$ which is not sufficient either.

IMO E

_________________

Lahoosaher

Re: stationery store   [#permalink] 01 Jun 2009, 14:30
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