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In a survey, 56 percent of the people surveyed stated

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In a survey, 56 percent of the people surveyed stated [#permalink] New post 06 Mar 2006, 13:56
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In a survey, 56 percent of the people surveyed stated truthfully that they were married, while 30 percent of the people surveyed who were married at that time chose not to include that information in the survey. What percent of the people surveyed were actually married at the time of the survey?

A. 20%
B. 60%
C. 40%
D. 75%
E. 80%
[Reveal] Spoiler: OA

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Last edited by Bunuel on 25 Oct 2013, 13:28, edited 1 time in total.
Edited the question and added the OA.
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Re: PS+ Survey [#permalink] New post 06 Mar 2006, 16:32
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bewakoof wrote:
In a survey, 56 percent of the people surveyed stated truthfully that they were married, while 30 percent of the people surveyed who were married at that time chose not to include that information in the survey. What percent of the people surveyed were actually married at the time of the survey?

1. 20
2. 60
3. 45
4. 70
5. 80



30% of married people that not reported it = (80*3)/10
equal to 24

24+56 = 80

there you go

80 it is
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 [#permalink] New post 06 Mar 2006, 21:30
you are right.. I thought this problem was very wordy and could not make sense of it under pressure.. thanks..
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 [#permalink] New post 09 Mar 2006, 18:12
conocieur's method is trial and error method. Substitute each Answer in the question and check if it is consistent with the information in the question.
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 [#permalink] New post 10 Mar 2006, 07:38
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let x be the % of ppl surveyed who were married.

56 + 0.3x = x

x = 80
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Re: In a survey, 56 percent of the people surveyed stated [#permalink] New post 25 Oct 2013, 12:42
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Re: In a survey, 56 percent of the people surveyed stated [#permalink] New post 16 Nov 2013, 01:04
No the solution still does not make sense to me. Let the total number of people surveyed be x.

56% stated they are married
30% stated they are not

How is the equation

56 + 0.3x = x derived here. Why are we not considering the remaining 14% people who were surveyed? I chose 80 as the answer only because it was close to 86 and luckily it is the answer here but please help me understand.
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Re: In a survey, 56 percent of the people surveyed stated [#permalink] New post 16 Nov 2013, 01:10
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aakrity wrote:
No the solution still does not make sense to me. Let the total number of people surveyed be x.

56% stated they are married
30% stated they are not(this is not out of the entire survey population). It is only 30% of those who are married.

How is the equation

56 + 0.3x = x derived here. Why are we not considering the remaining 14% people who were surveyed? I chose 80 as the answer only because it was close to 86 and luckily it is the answer here but please help me understand.


Let the total survey population be 100x. Now, 56x are married.

Again, let the total no of married people in the survey be 100y. Thus, 30% of them lied about being married. Thus, 70% were honest about it.

Thus, 70y = 56x

And, therefore 100y = 80x.

Thus, 80% were actually married.
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Re: In a survey, 56 percent of the people surveyed stated   [#permalink] 16 Nov 2013, 01:10
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