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In a village of 100 households, 75 have at least one DVD [#permalink]
23 Sep 2006, 08:48
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In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x^2-y^2 is a number from
(A) 1000 to 2500 (B) 2501 to 2800 (C) 2801 to 3000 (D) 3001 to 3100 (E) 3001 to 3150
The max number for X is 55.
The MIn is 100=210-( households with 2 of the items)-2( Households with all 3) the lowest value for households with all 3 items is when the households with 2 items are max or 108. Then we have only 1 household with all 3 items.
The ans is 54*56=3024 or D