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baner, would you break it down for me? I dont' know where I did wrong since I got a number with squre root >_<

Eqn of the line that passes thro 1,-2 and slope of -1 (as it is perpendicular to y = x) is: y = -x -1....(1)

Dist of 1,-2 from y = x ....is 3/sqrt 2.

We know that B is also same distance from the line only on the other side....if u draw these points and line in the xy plane u wud realize that B will approx land in y +ve and x -ve quadrant. We know that y = -x-1 intersect y axis at -1....

Now you have right triangle.....where we know the hypotenuous. Let x,y be the B coordinates. So we have....

9/2 = (x+1)^2 + y^2......(2)

Solve eq (1) and (2).....u wud get x = 4/8 or -2....4/8 is impossible...so
x = -2....and from eq 1....y = 1

B = (-2,1)......double check ur ans by calculating the dist from B to y=x...u will see it is also 3/sqrt 2. Draw it and u will see.

I don't think GMAT tests co-ordinate geometry to this level.

Ssumitsh:

The question is from REAL GMAT TEST

GMAT math is much harder than OG, OG is kind outdated, especially for Q

Agree tha this is of GMAT level.....but in GMAT u will have ans choices ...which u can quickly use and eliminate....once u know the eqn of a line.....here the ques didn't have any choices....so took longer.

The way you do this question is not to solve it algebrally. You draw a picture any you'll see all you need to do is to switch the x, y coordinations for the two points.

baner, would you break it down for me? I dont' know where I did wrong since I got a number with squre root >_<

Eqn of the line that passes thro 1,-2 and slope of -1 (as it is perpendicular to y = x) is: y = -x -1....(1)

Dist of 1,-2 from y = x ....is 3/sqrt 2.

We know that B is also same distance from the line only on the other side....if u draw these points and line in the xy plane u wud realize that B will approx land in y +ve and x -ve quadrant. We know that y = -x-1 intersect y axis at -1....

Now you have right triangle.....where we know the hypotenuous. Let x,y be the B coordinates. So we have....

9/2 = (x+1)^2 + y^2......(2)

Solve eq (1) and (2).....u wud get x = 4/8 or -2....4/8 is impossible...so x = -2....and from eq 1....y = 1

B = (-2,1)......double check ur ans by calculating the dist from B to y=x...u will see it is also 3/sqrt 2. Draw it and u will see.

Banerjee, could you please plainly expalain this again.thanks.

The way you do this question is not to solve it algebrally. You draw a picture any you'll see all you need to do is to switch the x, y coordinations for the two points.

Can you not use reflection point formula. if a segment is perpendicularly bisected by line x=y coordinations for the two points will be (a,b) & (b,a).

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