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Notice that the 6th term is 5 more than the 1st term, the 7th term is 5 more than the 2nd term, ..., the 10th term is 5 more than the 5th term, thus the sum of the last 5 terms is 5*5=25 greater than the sum of the first 5 terms. Therefore the answer is 560+25=585.

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]
06 Feb 2013, 02:05

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each of 5 last number is greater than each of 5 first number by 5.

we have 5 times 5=25 _________________

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