Find all School-related info fast with the new School-Specific MBA Forum

It is currently 30 May 2016, 20:05
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In an increasing sequence of 10 consecutive integers, the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

3 KUDOS received
Manager
Manager
avatar
Joined: 02 Dec 2012
Posts: 178
Followers: 3

Kudos [?]: 1598 [3] , given: 0

In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 07 Dec 2012, 04:31
3
This post received
KUDOS
6
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

76% (02:19) correct 24% (01:21) wrong based on 645 sessions

HideShow timer Statistics

In an increasing sequence of 10 consecutive integers, the sum of the first 5 integers is 560. What is the sum of the last 5 integers in the sequence?

(A) 585
(B) 580
(C) 575
(D) 570
(E) 565
[Reveal] Spoiler: OA
Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 33089
Followers: 5778

Kudos [?]: 70925 [1] , given: 9857

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 07 Dec 2012, 04:38
1
This post received
KUDOS
Expert's post
6
This post was
BOOKMARKED
Walkabout wrote:
In an increasing sequence of 10 consecutive integers, the sum of the first 5 integers is 560. What is the sum of the last 5 integers in the sequence?

(A) 585
(B) 580
(C) 575
(D) 570
(E) 565


Say our 10 consecutive integers are x, x+1, x+2, ..., x+9.

x+(x+1)+(x+2)+(x+3)+(x+4)=560.
(x+5)+(x+6)+(x+7)+(x+8)+(x+9)=?

Notice that the 6th term is 5 more than the 1st term, the 7th term is 5 more than the 2nd term, ..., the 10th term is 5 more than the 5th term, thus the sum of the last 5 terms is 5*5=25 greater than the sum of the first 5 terms. Therefore the answer is 560+25=585.

OR:
x+(x+1)+(x+2)+(x+3)+(x+4)=5x+10=560.
(x+5)+(x+6)+(x+7)+(x+8)+(x+9)=5x+35=(5x+10)+25=560+25=585.

Answer: A.
_________________

New to the Math Forum?
Please read this: All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

5 KUDOS received
VP
VP
avatar
Joined: 09 Jun 2010
Posts: 1229
Followers: 1

Kudos [?]: 82 [5] , given: 528

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 06 Feb 2013, 03:05
5
This post received
KUDOS
2
This post was
BOOKMARKED
each of 5 last number is greater than each of 5 first number by 5.

we have 5 times 5=25
1 KUDOS received
Intern
Intern
avatar
Joined: 15 Jan 2013
Posts: 39
Concentration: Finance, Operations
GPA: 4
Followers: 0

Kudos [?]: 25 [1] , given: 6

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 06 Feb 2013, 03:23
1
This post received
KUDOS
Walkabout wrote:
In an increasing sequence of 10 consecutive integers, the sum of the first 5 integers is 560. What is the sum of the last 5 integers in the sequence?

(A) 585
(B) 580
(C) 575
(D) 570
(E) 565




x+(x+1)+(x+2)+(x+3)+(x+4)=5x+10=560.
(x+5)+(x+6)+(x+7)+(x+8)+(x+9)=5x+35=(5x+10)+25=560+25=585.
3 KUDOS received
SVP
SVP
User avatar
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1858
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 35

Kudos [?]: 1526 [3] , given: 193

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 25 Mar 2014, 01:26
3
This post received
KUDOS
Let the 5 consecutive numbers be
x , x+1 , x+2 , x+3 , x+4

Given that there sum = 560

5 (x+2) = 560 ............ As they are consecutive; so sum will be middle term * 5

x+2 = 112

x = 110

So next five nos will be

115 , 116 , 117 , 118 , 119

There sum = 117 * 5 = 585 = Answer = A
_________________

Kindly press "+1 Kudos" to appreciate :)

Senior Manager
Senior Manager
avatar
Joined: 29 Oct 2013
Posts: 288
Concentration: Finance
Schools: Cornell AMBA'17
GMAT 1: 750 Q V46
GPA: 3.7
WE: Corporate Finance (Retail Banking)
Followers: 13

Kudos [?]: 302 [0], given: 188

GMAT ToolKit User
Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 28 May 2014, 09:36
tanviet wrote:
each of 5 last number is greater than each of 5 first number by 5.

we have 5 times 5=25


pure genius 10 sec approach! :)
_________________

Please consider giving 'kudos' if you like my post and want to thank :)

My journey V46 and 750 -> my-journey-to-46-on-verbal-750overall-171722.html#p1367876

Intern
Intern
avatar
Joined: 01 May 2013
Posts: 7
Schools: ISB '16
Followers: 0

Kudos [?]: 1 [0], given: 11

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 28 May 2014, 09:56
560 + 5*5 = 585, Option A)
Intern
Intern
avatar
Joined: 13 Dec 2013
Posts: 40
Schools: Fuqua (I), AGSM '16
GMAT 1: 620 Q42 V33
Followers: 2

Kudos [?]: 14 [0], given: 10

GMAT ToolKit User
Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 20 Jul 2014, 20:26
Average of 1st five numbers:

560/5 = 112 Since there are 5 numbers, the average is in the middle of the set, thus being the 3rd number.

110 111 112 113 114 ... now you just add the other consecutive 5 to equal 585.

This is a more organic approach if algebra is rusty.
1 KUDOS received
Intern
Intern
avatar
Joined: 06 May 2013
Posts: 2
Followers: 0

Kudos [?]: 1 [1] , given: 226

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 19 Feb 2015, 15:27
1
This post received
KUDOS
This is my approach:
X+x+1+x+2+x+3+x+4=560
5x+10=560
x=110
Total sum=10/2(2(110)+1(10-1))=5(229)=1145
Total sum- sum of first five terms=1145-560=585
Intern
Intern
User avatar
Joined: 27 Oct 2015
Posts: 18
Followers: 2

Kudos [?]: 2 [0], given: 175

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 02 Feb 2016, 07:55
thangvietnam
deepakpandey028

thx so much for ur incredible solution, cud i ask u to give a broader explanation?


thangvietnam wrote:
each of 5 last number is greater than each of 5 first number by 5.
we have 5 times 5=25


deepakpandey028 wrote:
560 + 5*5 = 585, Option A)
Expert Post
Math Forum Moderator
avatar
Joined: 20 Mar 2014
Posts: 2606
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
Followers: 97

Kudos [?]: 1092 [0], given: 777

In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 02 Feb 2016, 08:04
Expert's post
studentsensual wrote:
thangvietnam
deepakpandey028

thx so much for ur incredible solution, cud i ask u to give a broader explanation?


thangvietnam wrote:
each of 5 last number is greater than each of 5 first number by 5.
we have 5 times 5=25


deepakpandey028 wrote:
560 + 5*5 = 585, Option A)


Assume that the terms of the sequence are

x
x+1
x+2
x+3
x+4

x+5
x+6
x+7
x+8
x+9

When you compare x with x+5 or x+1 with x+6, the difference is always = x+5-x = 5

Thus you can make 5 pairs
(x,x+5)
(x+1,x+6)
(x+2,x+7)
(x+3,x+8)
(x+4,x+9), each with a difference of 5.

Thus sum of the last 5 terms = (x+5)+ (x+6)+ (x+7)+ (x+8)+ (x+9) = x+(5) + (x+1)+(5) + (x+2)+(5)+(x+3)+(5)+(x+4)+(5)

= x+(x+1)+(x+2)+(x+3)+(x+4)+5*5= 560+25 (as you are given that the sum of the 1st 5 terms of the sequence (=x+(x+1)+(x+2)+(x+3)+(x+4)) = 560.

Thus the sum of the last 5 terms = 585.

A is thus the correct answer.

Hope this helps.
_________________

Thursday with Ron updated list as of July 1st, 2015: http://gmatclub.com/forum/consolidated-thursday-with-ron-list-for-all-the-sections-201006.html#p1544515
Rules for Posting in Quant Forums: http://gmatclub.com/forum/rules-for-posting-please-read-this-before-posting-133935.html
Writing Mathematical Formulae in your posts: http://gmatclub.com/forum/rules-for-posting-please-read-this-before-posting-133935.html#p1096628
GMATCLUB Math Book: http://gmatclub.com/forum/gmat-math-book-in-downloadable-pdf-format-130609.html
Everything Related to Inequalities: http://gmatclub.com/forum/inequalities-made-easy-206653.html#p1582891
Inequalities tips: http://gmatclub.com/forum/inequalities-tips-and-hints-175001.html
Debrief, 650 to 750: http://gmatclub.com/forum/650-to-750-a-10-month-journey-to-the-score-203190.html

Intern
Intern
User avatar
Joined: 27 Oct 2015
Posts: 18
Followers: 2

Kudos [?]: 2 [0], given: 175

Re: In an increasing sequence of 10 consecutive integers, the [#permalink]

Show Tags

New post 02 Feb 2016, 09:45
Dear Engr2012,

Sincere thanks
You've been very helpful :)


Engr2012 wrote:
studentsensual wrote:
thangvietnam
deepakpandey028

thx so much for ur incredible solution, cud i ask u to give a broader explanation?


thangvietnam wrote:
each of 5 last number is greater than each of 5 first number by 5.
we have 5 times 5=25


deepakpandey028 wrote:
560 + 5*5 = 585, Option A)


Assume that the terms of the sequence are

x
x+1
x+2
x+3
x+4

x+5
x+6
x+7
x+8
x+9

When you compare x with x+5 or x+1 with x+6, the difference is always = x+5-x = 5

Thus you can make 5 pairs
(x,x+5)
(x+1,x+6)
(x+2,x+7)
(x+3,x+8)
(x+4,x+9), each with a difference of 5.

Thus sum of the last 5 terms = (x+5)+ (x+6)+ (x+7)+ (x+8)+ (x+9) = x+(5) + (x+1)+(5) + (x+2)+(5)+(x+3)+(5)+(x+4)+(5)

= x+(x+1)+(x+2)+(x+3)+(x+4)+5*5= 560+25 (as you are given that the sum of the 1st 5 terms of the sequence (=x+(x+1)+(x+2)+(x+3)+(x+4)) = 560.

Thus the sum of the last 5 terms = 585.

A is thus the correct answer.

Hope this helps.
Re: In an increasing sequence of 10 consecutive integers, the   [#permalink] 02 Feb 2016, 09:45
    Similar topics Author Replies Last post
Similar
Topics:
1 Experts publish their posts in the topic In an increasing sequence of 8 consecutive even integers, the sum of Bunuel 4 20 Dec 2015, 06:09
Experts publish their posts in the topic If a sequence of 8 consecutive odd integers with increasing values has Bunuel 3 09 Nov 2015, 23:12
11 Experts publish their posts in the topic Sequence S consists of 16 consecutive integers. If -6 is the enigma123 11 01 Mar 2012, 15:28
1 Experts publish their posts in the topic For any sequence of n consecutive positive integers, Se eybrj2 4 24 Feb 2012, 23:02
11 Experts publish their posts in the topic In an increasing sequence of 10 consecutive integers, the su MBAhereIcome 7 30 Aug 2011, 03:59
Display posts from previous: Sort by

In an increasing sequence of 10 consecutive integers, the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.