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# In an office, 40 percent of the workers have at least 5

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Eternal Intern
Joined: 07 Jun 2003
Posts: 473
Location: Lone Star State
Followers: 1

Kudos [?]: 41 [0], given: 0

In an office, 40 percent of the workers have at least 5 [#permalink]  25 Jul 2003, 20:33
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In an office, 40 percent of the workers have at least 5 years of service, and a total of 16 workers have at least 10 years of service. If 90 percent of the workers have fewer than 10 years of service, how many of the workers have at least 5 but fewer than 10 years of service?
SVP
Joined: 03 Feb 2003
Posts: 1611
Followers: 6

Kudos [?]: 74 [0], given: 0

Since 16 persons work for at least 10 years, they represent 10% of all workers (160).

Of 160 workers, 40% work for 5 years or more = 0.4*160= 64 This number includes those who work for at least 10 years.

Finally, the number of people who work for 5 years or more but fewer than 10 is 64-16=48

years _______5***********10******** (64 people -- 5 years or more)
_________________________+++++++ (16 people -- 10 years or more)
Eternal Intern
Joined: 07 Jun 2003
Posts: 473
Location: Lone Star State
Followers: 1

Kudos [?]: 41 [0], given: 0

It helps to know at least means at the minimum. So at least 10 years means 10 years at the minimum. Native speaker didn't know this?
Eternal Intern
Joined: 07 Jun 2003
Posts: 473
Location: Lone Star State
Followers: 1

Kudos [?]: 41 [0], given: 0

Yes 48, stolyar, my buddy in Moscow

I was just mentioning ETS wording and how it does no favor for non-native speakers.
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