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# In an office, 40 percent of the workers have at least 5

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Manager
Joined: 07 Jul 2003
Posts: 56
Followers: 2

Kudos [?]: 0 [0], given: 0

In an office, 40 percent of the workers have at least 5 [#permalink]  10 Feb 2004, 13:53
In an office, 40 percent of the workers have at least 5 years of service, and a total of 16 workers have at least 10 years of service. If 90 percent of the workers have fewer than 10 years of service, how many of the workers have at least 5 but fewer than 10 years of service?
Senior Manager
Joined: 05 May 2003
Posts: 427
Location: Aus
Followers: 2

Kudos [?]: 5 [0], given: 0

48 ??

No of workers who have atleast 10 years of exp = 16
% of workers who have less than 10 years = 90%

So, the total number of workers is 10%(x)= 16
x= 160

40%(160) = 64

Then subtract 16 from 64.
GMAT Club Legend
Joined: 15 Dec 2003
Posts: 4312
Followers: 28

Kudos [?]: 219 [0], given: 0

Agree with 48. Used a diagram:

---- <10 ---- >10 ---- Total

<5 ---- 96 ---- N/A ---- 96

>5 ---- 48 ---- 16 ---- 64

Total - 144 ---- 16 ---- 160
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Paul

SVP
Joined: 30 Oct 2003
Posts: 1797
Location: NewJersey USA
Followers: 5

Kudos [?]: 41 [0], given: 0

Got 48 as well.

0.4T = workers >=5 years so
0.6T = worker <5 years

0.4T = (6-9) years + (>10 years)

From the stem >10 years = 16

So (6-9) years = 0.4T - 16
Also from the stem
0.9T = (6-9) years + <5 years
0.9T = 0.4T-16 + 0.6T
T = 160

0.4 * 160 = (6-9) years + 16
Hence
(6-9) years = 64-16 = 48
Manager
Joined: 28 Jan 2004
Posts: 203
Location: India
Followers: 2

Kudos [?]: 14 [0], given: 4

48. Exactly the same solution as Geethu's.
Thats the easiest way to do this.
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