Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 07 Jul 2015, 16:14

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In an office, 40 percent of the workers have at least 5

Author Message
TAGS:
Manager
Joined: 05 Sep 2007
Posts: 144
Location: New York
Followers: 1

Kudos [?]: 20 [0], given: 0

In an office, 40 percent of the workers have at least 5 [#permalink]  31 Mar 2008, 18:38
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
In an office, 40 percent of the workers have at least 5 years of service, and a total of 16 workers have at least 10 years of service. If 90 percent of the workers have fewer than 10 years of service, how many of the workers have at least 5 but fewer than 10 years of service?

(A) 48
(B) 64
(C) 50
(D) 144
(E) 160
Intern
Joined: 28 Mar 2008
Posts: 34
Followers: 0

Kudos [?]: 3 [0], given: 0

Re: PS: workers [#permalink]  31 Mar 2008, 19:15
And going for the trifecta..

What we know
employees >= 5 = 40% -- 1
employees <10 = 90 %
This implies that 10% of the employees have >= 10yrs experience. -- 2
We are also given that 16 employees have greater than 10 yrs experience.

If n is the total number of employees. 0.1n=16 or n = 160

out of these 30% are in the range, [ 5 < yrs of experience < 10 ]
(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).

Man it took 3 minutes longer to type the answer than it took to solve the problem.

Last edited by daszero on 31 Mar 2008, 19:20, edited 1 time in total.
Intern
Joined: 31 Mar 2008
Posts: 14
Followers: 0

Kudos [?]: 1 [0], given: 0

Re: PS: workers [#permalink]  31 Mar 2008, 19:18
W = total workers

at least 5: W * .4
at least 10: 16
<10: W * .9

W = W * .9 + 16
.1W = 16
W = 160

5 <= x < 10
x = W * .4 - 16 = 48
SVP
Joined: 04 May 2006
Posts: 1936
Schools: CBS, Kellogg
Followers: 19

Kudos [?]: 491 [0], given: 1

Re: PS: workers [#permalink]  31 Mar 2008, 21:51
daszero wrote:
And going for the trifecta..

What we know
employees >= 5 = 40% -- 1
employees <10 = 90 %
This implies that 10% of the employees have >= 10yrs experience. -- 2
We are also given that 16 employees have greater than 10 yrs experience.

If n is the total number of employees. 0.1n=16 or n = 160

out of these 30% are in the range, [ 5 < yrs of experience < 10 ]
(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).

Man it took 3 minutes longer to type the answer than it took to solve the problem.

I used the table to solve it, but I lost in the gem. Could you figure out the boldface and colored above? I still not get it. Thank you!
_________________
Intern
Joined: 28 Mar 2008
Posts: 34
Followers: 0

Kudos [?]: 3 [0], given: 0

Re: PS: workers [#permalink]  01 Apr 2008, 11:21
sondenso wrote:
daszero wrote:
And going for the trifecta..

What we know
employees >= 5 = 40% -- 1
employees <10 = 90 %
This implies that 10% of the employees have >= 10yrs experience. -- 2
We are also given that 16 employees have greater than 10 yrs experience.

If n is the total number of employees. 0.1n=16 or n = 160

out of these 30% are in the range, [ 5 < yrs of experience < 10 ]
(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).

Man it took 3 minutes longer to type the answer than it took to solve the problem.

I used the table to solve it, but I lost in the gem. Could you figure out the boldface and colored above? I still not get it. Thank you!

Let me rephrase the answer, lets see if this conveys it better .

The problem says that 40% of the employees have work experience of at least 5 years

The problem also says that 16 employees have work experience of at least 10 years.

If the total number of employees = n,

the number of people who are between 5 and 10 years of experience = $$((40/100) * n) - 16$$ -- 1

The problem also says that 90% of employees have < 10 years experience. From this statement we see that the 16 employees who have more than 10 years of experience, constitute only 10% of the work force.

Thus $$(10/100) * n =16$$

Solving for this we get n=160. Substitute this in 1 and the answer works out to 48..
Director
Joined: 05 Jan 2008
Posts: 707
Followers: 3

Kudos [?]: 158 [0], given: 0

Re: PS: workers [#permalink]  01 Apr 2008, 12:10
it is a Straight A ->

If 90 percent of the workers have fewer than 10 years of service =>a total of 16 workers have at least 10 years of service represent 10%

thus 10% =16=> 100% is 160

how many of the workers have at least 5 but fewer than 10 years of service=> Given 40 percent of the workers have at least 5 years of service thus 40% = 64 BUT the 40% also involves the 16 folks who have more than 10 yrs of service thus 64-16 =48
_________________

Persistence+Patience+Persistence+Patience=G...O...A...L

Manager
Joined: 05 Sep 2007
Posts: 144
Location: New York
Followers: 1

Kudos [?]: 20 [0], given: 0

Re: PS: workers [#permalink]  01 Apr 2008, 12:25
daszero wrote:
And going for the trifecta..

What we know
employees >= 5 = 40% -- 1
employees <10 = 90 %
This implies that 10% of the employees have >= 10yrs experience. -- 2
We are also given that 16 employees have greater than 10 yrs experience.

If n is the total number of employees. 0.1n=16 or n = 160

out of these 30% are in the range, [ 5 < yrs of experience < 10 ]
(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).

Man it took 3 minutes longer to type the answer than it took to solve the problem.

I can't understand how did you come up with 30%? Please clarify this :
out of these 30% are in the range, [ 5 < yrs of experience < 10 ]
(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).
Intern
Joined: 28 Mar 2008
Posts: 34
Followers: 0

Kudos [?]: 3 [0], given: 0

Re: PS: workers [#permalink]  02 Apr 2008, 11:16
el1981 wrote:
daszero wrote:
And going for the trifecta..

What we know
employees >= 5 = 40% -- 1
employees <10 = 90 %
This implies that 10% of the employees have >= 10yrs experience. -- 2
We are also given that 16 employees have greater than 10 yrs experience.

If n is the total number of employees. 0.1n=16 or n = 160

out of these 30% are in the range, [ 5 < yrs of experience < 10 ]
(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).

Man it took 3 minutes longer to type the answer than it took to solve the problem.

I can't understand how did you come up with 30%? Please clarify this :
out of these 30% are in the range, [ 5 < yrs of experience < 10 ]
(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).

> =5 yrs = 40%
>=10 yrs = $$(16/160) *100$$ = 10%

Between 5 and 10 yrs = 40-10 = 30%
Re: PS: workers   [#permalink] 02 Apr 2008, 11:16
Similar topics Replies Last post
Similar
Topics:
6 Before a salary hike, the weekly salary of a worker for 40 5 10 Nov 2012, 13:04
7 If 40 percent of all students at college X have brown hair a 12 09 Mar 2011, 22:09
40% of the employees in a factory are workers... 2 08 Oct 2010, 04:37
In an office, 40 percent of the workers have at least 5 5 05 Jun 2007, 00:18
Display posts from previous: Sort by