to find the points on x axis, u have to put y=0 and not x=0
if c is negative, b^2 - 4ac will be positive and hence there will be two real roots.
Hence statement 2 alone is enough to solve the problem where as statement 1 alone is not.
Hmm. What if a was a large negative number and 4ac > b^2?
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993