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In City Y last year, what was the ratio of the number of

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Intern
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In City Y last year, what was the ratio of the number of [#permalink] New post 20 Nov 2005, 14:10
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In City Y last year, what was the ratio of the number of commuters who rode buses to the number of commuters who rode trains?

1. In City Y last year, 50,000 commuters rode trains and 48,000 commuters rode buses.
2. In City Y last year, if the number of commuters who rode trains had been 20 percent greater, the number of commuters who rode trains would have been 125percent of the number of commuters who rode buses.
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Re: DS-Ratio [#permalink] New post 20 Nov 2005, 14:28
My answer is D

Question asks B/T?

(1) Ratio = 48,000/50,000 = 24/25

(2) Let T = Number of commuters who rode trains
Let B = Number of commuters who rode buses

1.20T = 1.25B, after simplyfying, we can find the ratio is 24/25 as well
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 [#permalink] New post 21 Nov 2005, 12:06
D


In City Y last year, what was the ratio of the number of commuters who rode buses to the number of commuters who rode trains?

1. In City Y last year, 50,000 commuters rode trains and 48,000 commuters rode buses.
B/T=48,000 /50000

Suff

2. In City Y last year, if the number of commuters who rode trains had been 20 percent greater, the number of commuters who rode trains would have been 125percent of the number of commuters who rode buses.

T*120/100=B*125/100

suff

hence D
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Re: DS-Ratio [#permalink] New post 23 Nov 2005, 04:15
TeHCM wrote:
My answer is D

Question asks B/T?

(1) Ratio = 48,000/50,000 = 24/25

(2) Let T = Number of commuters who rode trains
Let B = Number of commuters who rode buses

1.20T = 1.25B, after simplyfying, we can find the ratio is 24/25 as well


Perfectly explained and easy to follow. Concur with TeHCM: (D)
Re: DS-Ratio   [#permalink] 23 Nov 2005, 04:15
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