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Manager
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In each production lot for a certain toy, 25 percent of the [#permalink]
 24 Mar 2008, 13:36
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In each production lot for a certain toy, 25 percent of the toys are red and 75 percent of the toys are blue. Half the toys are size A and half are size B. If 10 out of a lot of 100 toys are red and size A, how many of the toys are blue and size B?
(A) 15 (B) 25 (C) 30
(D) 35 (E) 40
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Senior Manager
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D-35
25 are Red - 10 are Size A - so 15 are Size B
75 are Blue - 40 are Size A and 35 are Size B (because there 50 toys each with sizes A and B)
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Intern
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100 toys total.
25 red, 75 blue.
50 A, 50 B.
10 red/A, therefore, 15 red/B.
We have 40 left in A and 35 left in B.
Therefore, 35 in blue/B.
I think.
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Director
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Given 100 Toys in total.
So toal read toys = 25
Total blue toys = 75
Total size A = 50
Total size B = 50
Total Red and Size A = 10
So Remaining Red toys will be all size B = 25 - 10 = 15
Remaining Size B toys which must come from Blue toys = 50 - 15 = 35
Answer D.
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Manager
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wow, i did it this way and got it wrong. Anyone know what i did wrong please explain to me.
1/4*1/2=1/8 sizeA and red.
3/4*1/2=3/8 sizeB and blue.
3/8*100=37.5
where did my logic go wrong here?
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Director
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You cannot multiply as you did because It is not necessary that half of red toys are size A and remaining half are size B. Similarly it is also not necessary that half of blue toys are size A and remaining half are size B.
But by your calculation you are assuming just that. Thereby the flaw.
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