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In how many different ways can 4 teachers and 4 students sit

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In how many different ways can 4 teachers and 4 students sit [#permalink] New post 01 Jun 2005, 03:38
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In how many different ways can 4 teachers and 4 students sit around the table so that only 1 student can be placed between 2 teachers?

a)210 b)180 c)160 d)144 e)120

Please explain your answer.
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 [#permalink] New post 01 Jun 2005, 12:32
Dan wrote:
I'll go for d.

(4-1)! * 4! = 144.


Dan, could you please give details of your calculation?
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 [#permalink] New post 01 Jun 2005, 19:42
since it is a circular perm, teachers can be arranged in (4-1)! Once this is done, students can be arranged 4! ways in between.

total arrangements = (4-1)! * 4!
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 [#permalink] New post 01 Jun 2005, 22:22
Dan wrote:
since it is a circular perm, teachers can be arranged in (4-1)! Once this is done, students can be arranged 4! ways in between.

total arrangements = (4-1)! * 4!


Thanks, Dan. Initially, I thought teachers and students can be regarded as 1 person in the following pattern: TS TS TS TS. Then, permutation would be 3!*2*2*2*2. What's wrong with this approach?

By the way, the OA is D.
  [#permalink] 01 Jun 2005, 22:22
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In how many different ways can 4 teachers and 4 students sit

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