jaykayes wrote:
akadiyan wrote:
The number of arrangements of n distinct objects in a circle is given by (n-1)!.
Now, 5 men can be arranged in (5-1)! = 4!
We can place 5 women in empty slots between Men so that no women will be together and also no men will be together.
The number of arrangements of 5 women is 5!
The answer is 4!5!
Ans C
I understand how you did the first step, i.e., 5 men can be arranged in 4! ways around a circular table.
But in the next step, we have 5 empty slots between the 5 men.
These empty slots are also in a circular arrangement.
So, if 5 women are to be arranged in these 5 slots, the number of arrangements should also be 4!, right?
Therefore, the answer should be 4! x 4!, i.e., answer choice A.
I'm wondering how you got 5! for the second step... please explain!
Thanks in advance.
The arrangement of n distinct objects in a row is denoted by n!.
The arrangement of n distinct objects in a circle is represented by (n-1)!.
The distinction between arranging in a row and in a circle is as follows: if we shift all objects by one position, we achieve a different arrangement in a row, but maintain the same relative arrangement in a circle. Therefore, for the number of circular arrangements of n objects, we have:
\(\frac{n!}{n} = (n-1)!\).
To demonstrate this, let's consider a simpler case: {1, 2, 3} arrangement in a row is distinct from {3, 1, 2} and from {2, 3, 1} arrangement.
However, the below three arrangements in a circle are identical:
Next, if we place three letters a, b, and c between these numbers, shifting them by one position would no longer yield the same arrangement. This is because it now matters whether a is positioned between 1 and 3 or between 1 and 2:
Therefore, the number of arrangements of a, b, and c between 1, 2, and 3 is now 3!, rather than 2!, due to the relative positioning of these letters in regards to the numbers.
Hope it's clear.
Attachment:
Arrangements in a cricle.png
Attachment:
Arrangements in a cricle2.png