n people can be seated around a round table in (n-1)! ways.
ok...let's find the no of ways in which that person is always seated next to 2 particular people.these 3 can be seated in 2 ways because the cetre position is fixed.
now we have a total of 3+1 people...note that 1 represents the group of those 3 people.
so 4 can be seated in (4-1)! ways = 6 ways.
hence total ways when 2 particular people are always next to one particular of them = 2*6=12 ways..
and total no of ways in which 6 people can be seated =(6-1)!=120 ways..
hence answer= 120=12 = 108 ways.
choice b as per me.
what's the OA?
In how many ways can 6 people be seated at a round table if one of those seated cannot sit next to 2 of the other 5?