Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 04 May 2015, 18:30

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In how many ways can a team of 11 cricketers be chosen from

Author Message
TAGS:
Director
Joined: 24 Oct 2005
Posts: 660
Location: London
Followers: 1

Kudos [?]: 7 [0], given: 0

In how many ways can a team of 11 cricketers be chosen from [#permalink]  25 Nov 2005, 04:08
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
In how many ways can a team of 11 cricketers be chosen from 6 bowlers, 4 wicket keepers and 11 batsmen to give a majority of batsmen if atleast 4 bowlers are to be included and there is 1 wicket keeper.
Director
Joined: 13 Nov 2003
Posts: 793
Location: BULGARIA
Followers: 1

Kudos [?]: 27 [0], given: 0

the only possible option is 4 blrs, 1wk and 6 batsmen if i understand the q correctly. This can be done in 6C4x4C1x11C6 =15x4x462=27720 ways
SVP
Joined: 28 May 2005
Posts: 1743
Location: Dhaka
Followers: 6

Kudos [?]: 72 [0], given: 0

Re: Permutation/ Combination - PS [#permalink]  25 Nov 2005, 11:21
remgeo wrote:
In how many ways can a team of 11 cricketers be chosen from 6 bowlers, 4 wicket keepers and 11 batsmen to give a majority of batsmen if atleast 4 bowlers are to be included and there is 1 wicket keeper.

if you want to include majority batsman and atleast 4 bowlers then

it can be 4bolwers, 6 batters 1wk
= 6C4*11C5*4C1 =15*462*4 = 27720
_________________

hey ya......

Director
Joined: 24 Oct 2005
Posts: 660
Location: London
Followers: 1

Kudos [?]: 7 [0], given: 0

Yes ans = 27720.

1 wicket keeper can be selected in C(4,1) ways
4 bowlres chosen = C(6,4)
Remaining 6 batsmen = C(11,6)

Total possibilities = C(4,1) * C(6,4) * C(11,6) = 27720.

The batsmen has to be majority. So the split cannot be 1WC, 5Bowlers, 5Batsmen.
It can only be 1WC, 4bowlers and 6batsmen.
Similar topics Replies Last post
Similar
Topics:
How many ways are there to create four teams of three from a 12 05 Aug 2008, 21:30
3 In how many ways can a soccer team finish the season with 3 11 07 Feb 2008, 11:28
In how many ways can a group of 8 be divided into 4 teams of 4 24 Aug 2007, 08:04
1 In how many ways can a group of 8 be divided into 4 teams of 9 22 Dec 2006, 21:37
In how many ways can a jury of 12 be chosen from 10 men and 2 26 Nov 2005, 12:53
Display posts from previous: Sort by