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# in how many ways can you seat 3 students in a row of 10

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Current Student
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in how many ways can you seat 3 students in a row of 10 [#permalink]

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07 Nov 2007, 14:01
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

in how many ways can you seat 3 students in a row of 10 empty chairs...no restrictions.
CEO
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Re: concept review [#permalink]

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07 Nov 2007, 14:04
young_gun wrote:
in how many ways can you seat 3 students in a row of 10 empty chairs...no restrictions.

10C3
=10! / 7!3!
= (10*9*8)/(3*2)
=5 * 3 *8
=3*40
=120
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Re: concept review [#permalink]

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07 Nov 2007, 18:07
bmwhype2 wrote:
young_gun wrote:
in how many ways can you seat 3 students in a row of 10 empty chairs...no restrictions.

10C3
=10! / 7!3!
= (10*9*8)/(3*2)
=5 * 3 *8
=3*40
=120

Again the 3 students can be arranged among themselves in 3! ways

= 120*6 = 720
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Re: concept review [#permalink]

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07 Nov 2007, 19:36
trivikram wrote:
bmwhype2 wrote:
young_gun wrote:
in how many ways can you seat 3 students in a row of 10 empty chairs...no restrictions.

10C3
=10! / 7!3!
= (10*9*8)/(3*2)
=5 * 3 *8
=3*40
=120

Again the 3 students can be arranged among themselves in 3! ways

= 120*6 = 720

agreed.

= 10 x 9 x 8
= 720
CEO
Joined: 29 Mar 2007
Posts: 2583
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Re: concept review [#permalink]

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07 Nov 2007, 22:23
young_gun wrote:
in how many ways can you seat 3 students in a row of 10 empty chairs...no restrictions.

If ur familiar w/ MGMAT method try usin anagram method

We have: students ABC seats XXXXXXXXXX

So 3 students will occupy 3 seats so
XXXXXXXXXX
123 NNNNNNN

Essentially its written like this 10!/1!1!1!7! --->
10*9*8-> 720
Re: concept review   [#permalink] 07 Nov 2007, 22:23
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# in how many ways can you seat 3 students in a row of 10

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