Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 29 Aug 2016, 21:22

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In how many ways is it possible to put seven apples and

Author Message
Manager
Joined: 24 Jun 2003
Posts: 91
Location: Moscow
Followers: 1

Kudos [?]: 3 [0], given: 0

In how many ways is it possible to put seven apples and [#permalink]

### Show Tags

11 Aug 2003, 07:59
1
This post was
BOOKMARKED
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In how many ways is it possible to put seven apples and three oranges in two paper bags so that both bags to contain at least one orange and identical number of fruits?
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 210 [0], given: 0

### Show Tags

11 Aug 2003, 09:49
10C5=252 total fives out of ten, but we count them twice, for one five defines the other
so, it is 126

wrong fives (no oranges, all apples) 7C5=21
126-21=105
Manager
Joined: 24 Jun 2003
Posts: 146
Location: India
Followers: 2

Kudos [?]: 2 [0], given: 0

### Show Tags

15 Aug 2003, 00:35
stolyar wrote:
10C5=252 total fives out of ten, but we count them twice, for one five defines the other
so, it is 126

wrong fives (no oranges, all apples) 7C5=21
126-21=105

Stolyar,

Here's my line of thinking:

The ways in which this arrangement can be made are

BAG-1 BAG-2

1 Orng+4 App 2 Orng+3 App
2 Orng+3 App 1 Orng+4 App

Therefore, there are 2 ways in my opinion. What's the flaw in this argument?

The key difference is that I'm assuming all oranges to be similar and all apples to be similar, therefore no choosing is involved
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 210 [0], given: 0

### Show Tags

15 Aug 2003, 01:14
1 Orng+4 App OR 2 Orng+3 App (2 combinations) would be OK if you had 5 fruits. But you have 10.

Consider
you have 1 white and 1 black balls, in how many combinations you can take a pair of black and white? The only combination--one black plus one white.

Now you have 1 white and 10 black balls; the question is the same--how many combinations. One again?
Manager
Joined: 24 Jun 2003
Posts: 91
Location: Moscow
Followers: 1

Kudos [?]: 3 [0], given: 0

### Show Tags

18 Aug 2003, 08:33
Stolyar's approach is the best. The answer is 105
Display posts from previous: Sort by