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In June 2004, GMAT Club, a community of aspiring MBA [#permalink]
 14 Oct 2008, 22:51
Question Stats:
72% (01:23) correct
27% (00:36) wrong based on 1 sessions
In June 2004, GMAT Club, a community of aspiring MBA students, registered 810 new members. How many members from USA and Canada registered in the month of June 2004? 1. In June 2004, the ratio of new members from USA and Canada, Europe and Asia was 4:3:2 2. In June 2004, none of the members were from locations other than USA and Canada, Europe and Asia Source: GMAT Club Tests - hardest GMAT questions I am not getting the way ratio is given in stmt-1. can someone please explain the same.
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Re: challenge m02 #3 [#permalink]
14 Oct 2008, 23:01
Id go with C on this.
Statement 1 states that the ratio is 4:3:2 for US/canada:Europe:asia. BUt r there any other countries. No idea. Insufficent
Stement 2 states that there are no other countries other than US/Canada, Europe and asia. But u do not know the ratio. Hence insufficent.
Combining both, ud get the answer.
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Re: challenge m02 #3 [#permalink]
05 Nov 2008, 18:21
jackychamp wrote:
I am not getting the way ratio is given in stmt-1.
can someone please explain the same.
what exactly is unclear to you about the ratio?
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Re: challenge m02 #3 [#permalink]
05 Nov 2008, 18:41
jackychamp wrote: In June 2004, GMAT Club, a community of aspiring MBA students, registered 810 new members. How many members from USA and Canada registered in the month of June 2004?
1. In June 2004, the ratio of new members from USA and Canada, Europe and Asia was 4:3:2
2. In June 2004, none of the members were from locations other than USA and Canada, Europe and Asia
I am not getting the way ratio is given in stmt-1.
can someone please explain the same. The ans is C. Here is how I approached this Q: 1st ask yourself: what does the Q tell us?(US+Can)+Others=810 2nd question to ask yourself: what is needed to find the value of (US+Can)? to find value for (US+Can) we have to know value for the "Others". Having this in mind we can start evaluating anwer options: 1. if we were sure that (Europe+Asia)=Others than the info provided here would be sufficient. but there could be australia, arctica, and antarctica  2. tells us that in fact (Europe+Asia)=Others i.e. no arctica/antarctica/australia. but we have no #'s to plug in for the "Others" thus insufficient putting the two together: (US+Can):E:A=4:3:2 jackychamp here is a trick that should help you to work with ratios: 4:3:2 can be written (4*x):(3*x):(2*x) so 4x+3x+2x=810 now we just have to solve for x thus sufficient.
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Re: challenge m02 #3 [#permalink]
19 Jan 2009, 17:17
In June 2004, GMAT Club, a community of aspiring MBA students, registered 810 new members. How many members from USA and Canada registered in the month of June 2004?
1 In June 2004, the ratio of new members from USA and Canada, Europe and Asia was 4:3:2
2 In June 2004, none of the members were from locations other than USA and Canada, Europe and Asia
I don't see how point 1 alone is not sufficient. You know that
USA AND CANADA = 4
Europe = 3
Asia = 2
Using this information you can find out how many members registered for USA and Canada..why does point 2 need to be stated??
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There could be registered members from other parts of the world. say Africa. Then first statement would not be sufficient.
Second statement tells us that 'In June 2004, none of the members were from locations other than USA and Canada, Europe and Asia'
Taken together they would be sufficient.
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Either C, or E.
The answer depends on how to understand the ratio.
I have two options.
1.
USA + Canada / Europe / Asia
4 / 3 / 2
In this case the number of students from USA and Canada is 810/9*4= 360.
2. USA /Canada/ Europe and Asia
4 / 3 / 2
In this case the number in question is 810/8*(4+3)=720.
If this ambiquity was made on purpose, then the answer is E.
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EkaterinaZ wrote: Either C, or E.
The answer depends on how to understand the ratio.
I have two options.
1.
USA + Canada / Europe / Asia
4 / 3 / 2
In this case the number of students from USA and Canada is 810/9*4= 360.
2. USA /Canada/ Europe and Asia
4 / 3 / 2
In this case the number in question is 810/8*(4+3)=720.
If this ambiquity was made on purpose, then the answer is E. I think US and Canada were meant to be treated as single entity. C.
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EkaterinaZ wrote: Either C, or E.
The answer depends on how to understand the ratio.
I have two options.
1.
USA + Canada / Europe / Asia
4 / 3 / 2
In this case the number of students from USA and Canada is 810/9*4= 360.
2. USA /Canada/ Europe and Asia
4 / 3 / 2
In this case the number in question is 810/8*(4+3)=720.
If this ambiquity was made on purpose, then the answer is E. I chose E because to me the ratio wasn't clear. 1. In June 2004, the ratio of new members from USA and Canada, Europe and Asia was 4:3:2If it were stated In June 2004, the ratio of new members from USA and Canada, Europe , and Asia was 4:3:2 it might give more of a clue. I think EkaterinaZ brings up a good point. Are we wrong? It seems a little unclear to me.
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I'm trying to not just answer the problem but to explain how I came up with my answer. If I am incorrect or you have a better method please PM me your thoughts. Thanks!
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statement 1 alone is insufficient to answer the question. statement 2 alone is insufficient to answer the question. but combining together we can get the answer.
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In June 2004, GMAT Club, a community of aspiring MBA students, registered 810 new members. How many members from USA and Canada registered in the month of June 2004? 1. In June 2004, the ratio of new members from USA and Canada, Europe and Asia was 4:3:2 2. In June 2004, none of the members were from locations other than USA and Canada, Europe and Asia Answer is 'C'. Since the ratio seems to be unclear to me so I went with two options C and E. When the two statements in a DS question are unclear, the probability of answer being C then being E. So I went with a wild Guess of 'C'.( sometimes it works  )
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Obviously it is 'C'.
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Initially I though A is the answer.But correct ams should be C.
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Easy one. C is the answer.
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C. S1: there could be other places. S2: only this info is not enough. Combined s1 & s2 we can arrive at solution. Posted from my mobile device 
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Initially i choosd A, but after exploring the reasoning definetly it C . I think its little tricky. Cheers
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trezpazzer wrote: There could be registered members from other parts of the world. say Africa. Then first statement would not be sufficient.
Second statement tells us that 'In June 2004, none of the members were from locations other than USA and Canada, Europe and Asia'
Taken together they would be sufficient. does the gmat really have statements/implications like this. Or will we sometimes have to assume that because the ratio is given with the respective countries, those are the only countries that joined because they would have given the information from the other countries otherwise?
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C. Does not seem like GMAT type problem to me.
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Both statement together are sufficient. C total number of students are 810. s1: U&C : E:A = 4:3:2, as we do not know if any other reg is defined by GMAT club, hence not sufficent S2: not helpful to answer the qestion both statement put together is sufficent as 4x+3x+2x = 810 9X = 810 X = 81 US&C = 81*4
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-------Analyze why option A in SC wrong-------
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Re: In June 2004, GMAT Club, a community of aspiring MBA [#permalink]
07 Nov 2012, 06:21
S1. Not sufficient as we dont know if any other countries are resgistred ohter than these 3.. S2. Alone not suffient as ratio is not stated.. S1 +S2 = Suffiecint so answer C
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Re: In June 2004, GMAT Club, a community of aspiring MBA
[#permalink]
07 Nov 2012, 06:21
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