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In last examination Roger scored marks in each of 5 subjects

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In last examination Roger scored marks in each of 5 subjects [#permalink] New post 04 Mar 2012, 06:34
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In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!
[Reveal] Spoiler: OA

Last edited by Bunuel on 04 Mar 2012, 07:08, edited 1 time in total.
Edited the question and moved to PS subforum
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Re: Ratio question [#permalink] New post 04 Mar 2012, 07:07
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In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Given: A:B:C:D:E=4x:5x:6x:7x:8x, for some multiple x. Assume the maximum marks of each subject to be y, so the the maximum marks of ALL 5 subjects will be 5y.

So, we have that 4x+5x+6x+7x+8x=\frac{72}{100}*5y --> 30x=\frac{72*5}{100}*y --> x=\frac{12}{100}*y. 4x=\frac{48}{100}*y and 5x=\frac{60}{100}*y, so in subject A Roger scored 48% (less than 50%) and in subject B 60% (more than 50%). Obviously in all other subjects Rogers scores will be higher than 50%.

Roger failed in only one subject A.

Answer: A.

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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 04 Mar 2012, 07:17
Many thanks!!!

But I dont really get the step, to multiply with 5y

Could you please explain it to me.

Thanks!
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 04 Mar 2012, 07:41
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NYC5648 wrote:
Many thanks!!!

But I dont really get the step, to multiply with 5y

Could you please explain it to me.

Thanks!


We are told that "the maximum marks of each subject is the same", say it's y, then the sum of the marks in all 5 subjects will be y+y+y+y+y=5y.

Hope it's clear.
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 05 Mar 2012, 10:41
Hi bunnel

can you suggest any material for ratio and proportions. I have completed ratio and proportions in manhattan word translations, but still i need some extra practice

Thanks
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 05 Mar 2012, 10:59
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TomB wrote:
Hi bunnel

can you suggest any material for ratio and proportions. I have completed ratio and proportions in manhattan word translations, but still i need some extra practice

Thanks


I can think of no material on this subject though below are some questions to practice:
PS questions on Fractions/Ratios/Decimals: search.php?search_id=tag&tag_id=36
DS questions on Fractions/Ratios/Decimals: search.php?search_id=tag&tag_id=57

Hope it helps.
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 20 Mar 2012, 20:37
I did this by picking numbers.
Say the max mark in each subject is 100.
Then I can directly know that Roger scored 40,50,60,70,80.
Since passing mark is 50% of max mark => passing mark = 50.
Thus Roger failed in only 1 subject, where he scored 40.

Answer A.
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 23 Mar 2012, 03:48
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took x as a percentage of score in an exam

(4x+5x+6x+7x+8x)5 =72 = avg percentage
6x=72
x = 12

therefore marks are 48%, 60% and so on and only the one value 48% is below the passing threshold of 50%. Hence, A.
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 23 Mar 2012, 05:06
NYC5648 wrote:
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!


LET MAX MARKS BE Y

then (4+5+6+7+8)x=0.72*5y
=> 30x=3.6y
=> x=36y/300=3y/25
hence

4x= 4*3y/25=12y/25--> fail
5x--> pass
as all other scores are greater than 5x hence he passed in all

hence failed in 1 subject

option A
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 24 Jun 2013, 03:04
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 25 Jun 2013, 11:01
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NYC5648 wrote:
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!



For ratio and proportion questions, We can always check at first for plugging in values.

Let us assume that for each exam the max score is 100. So total max score in 5 exams is 500
where as Roger scored 72% of 500 which is 360

360 is total marks scored by Roger which is nothing but some of sum of his scores in all subjects

so we have 4a+5a+6a+7a+8a = 360 where "a" is any positive integer, solving for "a", we get 30a= 360 ----> a=12

4a= 48 < 50 and in rest all exams he passed so ans should be A
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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 03 Jan 2014, 07:03
NYC5648 wrote:
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!


Total sum of scores is 30x

Total sum of scores is also 720

720/30 = 12 = x

So then, we can start with the first and it will give 48, fail
Next is obviously 60 pass, so only 1 fail

Hence A

Hope it helps!
Cheers
J :)
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Re: Ratio question [#permalink] New post 08 Mar 2014, 07:57
Bunuel wrote:
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Given: A:B:C:D:E=4x:5x:6x:7x:8x, for some multiple x. Assume the maximum marks of each subject to be y, so the the maximum marks of ALL 5 subjects will be 5y.

So, we have that 4x+5x+6x+7x+8x=\frac{72}{100}*5y --> 30x=\frac{72*5}{100}*y --> x=\frac{12}{100}*y. 4x=\frac{48}{100}*y and 5x=\frac{60}{100}*y, so in subject A Roger scored 48% (less than 50%) and in subject B 60% (more than 50%). Obviously in all other subjects Rogers scores will be higher than 50%.

Roger failed in only one subject A.

Answer: A.

P.S. Please post PS questions in the PS subforum: gmat-problem-solving-ps-140/ and DS questions in the DS subforum: gmat-data-sufficiency-ds-141/

No posting of PS/DS questions is allowed in the main Math forum.


Bunuel - Could you walk me through how you reduced the fraction above (highlighted in blue)
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Re: Ratio question [#permalink] New post 08 Mar 2014, 08:03
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bparrish89 wrote:
Bunuel wrote:
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Given: A:B:C:D:E=4x:5x:6x:7x:8x, for some multiple x. Assume the maximum marks of each subject to be y, so the the maximum marks of ALL 5 subjects will be 5y.

So, we have that 4x+5x+6x+7x+8x=\frac{72}{100}*5y --> 30x=\frac{72*5}{100}*y --> x=\frac{12}{100}*y. 4x=\frac{48}{100}*y and 5x=\frac{60}{100}*y, so in subject A Roger scored 48% (less than 50%) and in subject B 60% (more than 50%). Obviously in all other subjects Rogers scores will be higher than 50%.

Roger failed in only one subject A.

Answer: A.

P.S. Please post PS questions in the PS subforum: gmat-problem-solving-ps-140/ and DS questions in the DS subforum: gmat-data-sufficiency-ds-141/

No posting of PS/DS questions is allowed in the main Math forum.


Bunuel - Could you walk me through how you reduced the fraction above (highlighted in blue)


30x=\frac{72*5}{100}*y=\frac{(6*12)*5}{100}*y --> reduce by 30=6*5: x=\frac{12}{100}*y --> multiply by 4: 4x=\frac{48}{100}*y.

Hope it's clear.
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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 08 Mar 2014, 09:24
Option A.
Let the marks be 4x,5x,6x,7x and 8x.
Total=30x
Avg.=6x
Now 6x=72
X=12
On calculating Subject marks,we get 48,60,72,84 & 96.
Only one subject is <50.

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Re: In last examination Roger scored marks in each of 5 subjects [#permalink] New post 09 Mar 2014, 02:26
monalimishra wrote:
I did this by picking numbers.
Say the max mark in each subject is 100.
Then I can directly know that Roger scored 40,50,60,70,80.
Since passing mark is 50% of max mark => passing mark = 50.
Thus Roger failed in only 1 subject, where he scored 40.

Answer A.


Though the answer A is correct, the calculations are wrong :(

If we consider 40,50,60,70,80 as the scores, then the average comes up 60%
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Re: In last examination Roger scored marks in each of 5 subjects   [#permalink] 09 Mar 2014, 02:26
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