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In order to complete a reading assignment on time, Terry [#permalink]

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11 Oct 2012, 09:22

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In order to complete a reading assignment on time, Terry planned to read 90 pages per day. However, she read only 75 pages per day at first, leaving 690 pages to be read during the last 6 days before the assignment was to be completed. How many days in all did Terry have to complete the assignment on time?

Re: In order to complete a reading assignment on time, Terry [#permalink]

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11 Oct 2012, 11:24

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nelz007 wrote:

In order to complete a reading assignment on time, Terry planned to read 90 pages per day. However, she read only 75 pages per day at first, leaving 690 pages to be read during the last 6 days before the assignment was to be completed. How many days in all did Terry have to complete the assignment on time?

Say Terry read at the rate of 75 pages per day for \(d\) days.

Now, in \(d\) days she read \(75d\) pages, and since after that 690 pages were left, then the number of pages in the book is \(75d+690\).

Next, we also know that she had \(d+6\) days for the assignment. Since Terry planned to read 90 pages per day for this number of days, then the number of pages in book is also equal to \(90(d+6)\).

So, we have that \(75d+690=90(d+6)\) --> \(d=10\). Thus, the total number of days that she has to complete the assignment on time is \(d+6=16\).

Here are my 50 cents We know that Distance = Time*Speed, thus in our case Distance is the assignment to be completed and T are those days and S is peed, the number of pages per day. From here we get: D=90*X - according to the plan, assignment to be completed on time reading 90 pages per day for next X days. But, Terry's plans changed so she read as follow: 75 pages for first Y days and 690 pages for last 6 days, we get these equations: 75*Y+690=90*X X-Y=6 --------->>X planned number of days, Y - actually used reading 75 pages per day and 6 leftover days used to complete a lump 690 pages From above we find that X=Y+6 and 75Y+690=90Y+540 or 15Y=150 --->>>>> Y=10, hence X=16 (B) Please, correct me if I went awry. _________________

Re: In order to complete a reading assignment on time, Terry [#permalink]

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12 Jun 2015, 03:24

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We can solve this one with weighted average method (see MGMAT) X*(-15) + 6*(25) = 0 X = 10 --> X+6 = 16 (B) Let be the first X days at a rate of 75 Pages - It's below planed average of 90 (-15), the last 6 days = 690/6 = 115 --> It's above the average of 90 (+25) _________________

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Re: In order to complete a reading assignment on time, Terry [#permalink]

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23 Dec 2012, 05:32

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I would like to give it a try too.

Initially the planned rate was supposed to be \(90 pages\) per day. So the total number of pages will come out to be \(90*t\) where t is the number of days required to complete the book, when done at the planned rate.

Now the study has been dirtributed. The person reads the book at the rate of \(75 pages\) per day for the \(t-6\) days and for the last \(6\) days, the person reads at \(115\) pages per day.

So the equation becomes \(90t=75(t-6) + 115*6\). On solving t comes as 16. Hence the answer. _________________

Re: In order to complete a reading assignment on time, Terry [#permalink]

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25 Oct 2013, 19:20

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Her original goal was to read 90pages per day. Thus in 6 days she would have read 90*6= 540 pages. Since she was left with 690 pages means she was 150pages short of target. Since the difference between 90 pages and 75 pages is 15 pages. The number of days would be 150/15 = 10 days Total number of days to complete assignment 10 + 6 days = 16days.

Re: In order to complete a reading assignment on time, Terry [#permalink]

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23 Dec 2012, 03:35

Well, How about plugging in.

Start off with C=25 days. We know that for 6 days its 690 pgs. So 25-6=19 days left Now we have to multiply 75 and 19=1425 Now add 1425 and 690= 2115 pgs But the planned rate is 90 pgs. Multi ply 90 and 25 we get 2250 pgs. This is more than 2115. So we need to plugin a lesser number. Plugin ans choice b and get the answer. _________________

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Re: In order to complete a reading assignment on time, Terry [#permalink]

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21 Sep 2013, 02:35

Initial rate :

90 = P/D Where P --> total number of pages. D --> total number of days.

New rate.

75 = P-690 / D-6

Solve both equations.

D=16 days. _________________

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Re: In order to complete a reading assignment on time, Terry [#permalink]

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20 Sep 2014, 07:32

nelz007 wrote:

In order to complete a reading assignment on time, Terry planned to read 90 pages per day. However, she read only 75 pages per day at first, leaving 690 pages to be read during the last 6 days before the assignment was to be completed. How many days in all did Terry have to complete the assignment on time?

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