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In ΔPQS above, if PQ =3 and PS = 4, then [#permalink]
 14 Aug 2009, 07:55
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In ΔPQS above, if PQ =3 and PS = 4, then (A) 9/4 (B) 12/5 (C) 16/5 (D) 15/4 (E)20/3
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[quote="vannu"]In ΔPQS above, if PQ =3 and PS = 4, then
(A)9/4
(B) 12/5
(C) 16/5
(D) 15/4
(E)20/3
i guess the question is asking about PR
this a pythagron triblet 3,4,5 , thus the hyp = 5
well
area of the triangle = 1/2 *3*4 = 6 ( using perpen sides)
area ( hyp and pr) = 6 , hyp = 5 thus pr = 12/5
pr = 6*2/5 = 12/5
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there are two ways to calculate area of PQS. area remains same, so both are equal. 3*4/2 = PR*5/2 PR = 12/5 *btw, this is known has "bh" principle i.e. PQ*PS = PR*QS.
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