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In the attached figure, what is the length of PQ times the

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In the attached figure, what is the length of PQ times the [#permalink] New post 10 Aug 2003, 13:36
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In the attached figure, what is the length of PQ times the length of RS?

(1) The length of PQ is 5
(2) The length of QR times the length of PR is equal to 12

What is sufficient? (1), (2), (both together), (both by themselves), (neither is sufficient)

I think there is an error in PR's solution to the problem.

This problem is from the 2004 edition (problem set)

Let me know what you think, and then i'll post the PR solution, as well as my solution.

Thanks,

Htown
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 [#permalink] New post 10 Aug 2003, 20:37
That is correct.

However, I chose D because I felt that A was sufficient as well.
Since RS is perpendicular to QP, can't you assume that QS is = to 2.5 (half of 5)? If that is the case, you can assume that SR is also 2.5 because Triangle QRS is a 90, 45, 45.

Now you have PQ as stated in (1) and SR which will give you what you need.

Obviously PR has a problem with me defining QS as 2.5

What do you think?

Htown
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 [#permalink] New post 10 Aug 2003, 22:32
htown wrote:
That is correct.

However, I chose D because I felt that A was sufficient as well.
Since RS is perpendicular to QP, can't you assume that QS is = to 2.5 (half of 5)? If that is the case, you can assume that SR is also 2.5 because Triangle QRS is a 90, 45, 45.

Now you have PQ as stated in (1) and SR which will give you what you need.

Obviously PR has a problem with me defining QS as 2.5

What do you think?

Htown


There is no justification for you to assume that QS is 2.5, even if it "looks" like it in the picture. All you know is that the hypotenuese of a right triangle is 5. The legs could be anything, hence the QS could be anything.
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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 [#permalink] New post 11 Aug 2003, 06:21
I agree that the legs could be "anything," but if you have a 45, 45, 90 triangle and you know one length, you have them all. How can RS form a perpendicular with PQ and not intersect at the midpoint of PQ?

Thanks

Htown
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 [#permalink] New post 11 Aug 2003, 14:15
htown wrote:
I agree that the legs could be "anything," but if you have a 45, 45, 90 triangle and you know one length, you have them all. How can RS form a perpendicular with PQ and not intersect at the midpoint of PQ?

Thanks

Htown


Draw ANY right triangle with its hypotenuese on the bottom. Now simply drop a line from the tip of the triangle to the hypotenuese, which is simply the attitude. Unless your triangle was a 45-45-90, the line you drop will certainly not bisect the hypotenuese but still be perpendicular to it.

Note: don't just ask questions, try some of these out for yourself.
_________________

Best,

AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

  [#permalink] 11 Aug 2003, 14:15
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