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(i) and (ii) are clearly insufficient on their own.

Rule out A,B,D.

With (i) n (ii) together:

- If Triangle PDC is equilateral, PCD = 60 and PCB = 30 as its a square.
- Triangle PBC is Isoceles with the angle opp to base = 30
- The other 2 angles CPB and CBP are hence (180-30)/2 = 75

how did u guys come to the conclusion that triangle PBC is isoscles? thanks siva

ABCD is a square. pdc is an egquilateral triangle that shares a side with square ABCD. Sides DC aand BC are clearly equal since they are part of the same square. Side PC = DC = BC. PC and BC form the second triangle with an angle of 30 degrees. A 30 degree angle with 2 equal sides proves that it is an isosceles triangle.

Hope it helps. Not sure I explained very well. Try drawing it out. It makes it much easier. The innacurate drawing could really throw ppl off.

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