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Notice that line l passes through points (3,0) and (0,2), so its slope is \(m=\frac{y_2-y_1}{x_2-x_1}=-\frac{2}{3}\) (given two points \((x_1,y_1)\) and \((x_2,y_2)\) on a line, the slope \(m\) of the line is \(m=\frac{y_2-y_1}{x_2-x_1}\)).

Only option B, when written in \(y=mx+b\) form has the slope of -2/3.

Answer: B.

Hi Bunnel...A small query Can we assume (As u have done in your solution) that the line passes through points (3,0) and (0,2). I mean can we safely interpret graphs on the GMAT??Since it is not explicitly stated that the line passes through those two specific points. My approach to the above problem was as follows. What we know from the graph is this x and y co-ordinates of line l are both positive, x co-ordinate is > 2 and y co-ordinate is > 1 Checking answer choices - A, D and E are clearly out since x and y co-ordinates will have opposite signs putting y=0 in choice C x=2 - Incorrect (as x co-ordinate > 2) Only B left Cheers

From the given figure, we can see that the line has positive intercept on both the x and y axis. Thus we can eliminate all the options except B and C. Now the intercept on the x-axis is more than 2. For option C, the x-intercept comes as 2, thus the answer has to be B. _________________

Without any calculation Approach! We know from the graph that X-intercept must be greater than 2. So, co-efficient of x must be 2. Hence C and E are out. The equation of straight line is y=mx+b and In the figure we can see that slope must be negative. Therefore, A and D are out since they have positive slope. Answer is B.

Notice that line l passes through points (3,0) and (0,2), so its slope is \(m=\frac{y_2-y_1}{x_2-x_1}=-\frac{2}{3}\) (given two points \((x_1,y_1)\) and \((x_2,y_2)\) on a line, the slope \(m\) of the line is \(m=\frac{y_2-y_1}{x_2-x_1}\)).

Only option B, when written in \(y=mx+b\) form has the slope of -2/3.

Notice that line l passes through points (3,0) and (0,2), so its slope is \(m=\frac{y_2-y_1}{x_2-x_1}=-\frac{2}{3}\) (given two points \((x_1,y_1)\) and \((x_2,y_2)\) on a line, the slope \(m\) of the line is \(m=\frac{y_2-y_1}{x_2-x_1}\)).

Only option B, when written in \(y=mx+b\) form has the slope of -2/3.

Answer: B.

Hi Bunnel...A small query Can we assume (As u have done in your solution) that the line passes through points (3,0) and (0,2). I mean can we safely interpret graphs on the GMAT??Since it is not explicitly stated that the line passes through those two specific points. My approach to the above problem was as follows. What we know from the graph is this x and y co-ordinates of line l are both positive, x co-ordinate is > 2 and y co-ordinate is > 1 Checking answer choices - A, D and E are clearly out since x and y co-ordinates will have opposite signs putting y=0 in choice C x=2 - Incorrect (as x co-ordinate > 2) Only B left Cheers

OG13 solution makes the same exact assumption "The line is shown going through the points (0,2) and (3,0)..." _________________

Re: In the coordinate system above, which of the following is [#permalink]

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07 Nov 2013, 23:41

Just a different way of approaching the problem... since we know the y-intercept is -c/b when the equation is given in the form ax+by +c =0.. simply use what's on the right side of the equation (it'll turn negative when moved to the left) and divide by b.

Notice that line l passes through points (3,0) and (0,2), so its slope is \(m=\frac{y_2-y_1}{x_2-x_1}=-\frac{2}{3}\) (given two points \((x_1,y_1)\) and \((x_2,y_2)\) on a line, the slope \(m\) of the line is \(m=\frac{y_2-y_1}{x_2-x_1}\)).

Only option B, when written in \(y=mx+b\) form has the slope of -2/3.

Answer: B.

Hi Bunnel...A small query Can we assume (As u have done in your solution) that the line passes through points (3,0) and (0,2). I mean can we safely interpret graphs on the GMAT??Since it is not explicitly stated that the line passes through those two specific points. My approach to the above problem was as follows. What we know from the graph is this x and y co-ordinates of line l are both positive, x co-ordinate is > 2 and y co-ordinate is > 1 Checking answer choices - A, D and E are clearly out since x and y co-ordinates will have opposite signs putting y=0 in choice C x=2 - Incorrect (as x co-ordinate > 2) Only B left Cheers

OG13 solution makes the same exact assumption "The line is shown going through the points (0,2) and (3,0)..."

I agree with Dipankar6435 approach. I used the similar approach since it is not explicitly mentioned that the line passes through and also there is no line markers at the points where the line touches both x and y axis. Since there is a line marker on the x axis that clearly indicates that the x value should be greater than 2, out of the 2 answer choices, I picked B as the right one. Thanks.

Notice that line l passes through points (3,0) and (0,2), so its slope is \(m=\frac{y_2-y_1}{x_2-x_1}=-\frac{2}{3}\) (given two points \((x_1,y_1)\) and \((x_2,y_2)\) on a line, the slope \(m\) of the line is \(m=\frac{y_2-y_1}{x_2-x_1}\)).

Only option B, when written in \(y=mx+b\) form has the slope of -2/3.

Answer: B.

Hi Bunnel...A small query Can we assume (As u have done in your solution) that the line passes through points (3,0) and (0,2). I mean can we safely interpret graphs on the GMAT??Since it is not explicitly stated that the line passes through those two specific points. My approach to the above problem was as follows. What we know from the graph is this x and y co-ordinates of line l are both positive, x co-ordinate is > 2 and y co-ordinate is > 1 Checking answer choices - A, D and E are clearly out since x and y co-ordinates will have opposite signs putting y=0 in choice C x=2 - Incorrect (as x co-ordinate > 2) Only B left Cheers

OG13 solution makes the same exact assumption "The line is shown going through the points (0,2) and (3,0)..."

Very very strange because in Maths , one is groomed to never make assumptions based on diagrams unless explicitly mentioned .

Re: In the coordinate system above, which of the following is [#permalink]

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17 May 2014, 06:11

There is another general form of line in co-ordinate plane which is:

x/a + y/b = 1

where a is the point of intersection of line and x-axis and b is the point of intersection of line with y-axis. Here a=3, b=2 Therefore,

x/3 + y/2 = 1

or

2x + 3y = 6

This solution is valid, if we assume the values of a, and b.

But even if we don’t assume these values, we can eliminate option A), D), and E) because, we can see that both the x intercept and y intercept are positive.

Now, we see a>b through observation, which means coefficient of x is greater than coefficient of y, which is in option B) only. Hence B is the answer.

Re: In the coordinate system above, which of the following is [#permalink]

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21 May 2014, 04:59

If intercept on the x axis and y axis is known, intercept formula for line is the fastest method to get the equation of the line.

Equation of a line which cut an intercept a at x axis and b at y axis is given by

(x/a) + (y/b) = 1

However, a more useful form of this equation is

bx + ay = ab

using this, equation of line can be found easily by inspection only Here , Intercept at x axis = a = 3 Intercept at y axis = b = 2 hence, equation of line by putting values 2x+3y =6 hence answer is B _________________

Re: In the coordinate system above, which of the following is [#permalink]

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09 Jul 2015, 11:42

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