clciotola wrote:

AB

+BA

---------

CDC

in the correctly worked computation above A, B, C and D represent distinct nonzero digits. What is the value of A+B+C+D

a 14

b 16

c 18

d 20

e it cannot be determined from given information

Sum of two double digit integers is 198 at the maximum.

So as CDC is a three digit number we have C = 1

CDC = 1D1

now A+B = some number which gives a carry and with units place as one.It must give a carry because if we add units ie A+B we are getting C and then if we add tens we get CD .So there must be a carry for tens place.

So by adding A and B we must get 11.(As the maximum carry we can get by adding two single digit numbers is 1 and also C = 1)

now D will be 2 as A+B + 1 = 12

so we will get CDC as 121.

Sum of the digits will be 11 + 1 + 2

ie 14

correct me if I am wrong

_________________

"Kudos" will help me a lot!!!!!!Please donate some!!!

Completed

Official Quant Review

OG - Quant

In Progress

Official Verbal Review

OG 13th ed

MGMAT IR

AWA Structure

Yet to do

100 700+ SC questions

MR Verbal

MR Quant

Verbal is a ghost. Cant find head and tail of it.