in the correctly worked computation above A, B, C and D represent distinct nonzero digits. What is the value of A+B+C+D
e it cannot be determined from given information
Sum of two double digit integers is 198 at the maximum.
So as CDC is a three digit number we have C = 1
CDC = 1D1
now A+B = some number which gives a carry and with units place as one.It must give a carry because if we add units ie A+B we are getting C and then if we add tens we get CD .So there must be a carry for tens place.
So by adding A and B we must get 11.(As the maximum carry we can get by adding two single digit numbers is 1 and also C = 1)
now D will be 2 as A+B + 1 = 12
so we will get CDC as 121.
Sum of the digits will be 11 + 1 + 2
correct me if I am wrong
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