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In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink ]
08 Mar 2013, 13:35
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78% (01:51) correct

21% (00:59) wrong

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two similar triangles.JPG [ 20.78 KiB | Viewed 846 times ]
In the diagram above, ∠J = ∠M, ∠K = ∠N, and side lengths are as shown. Given this, y must equal (A) r/sx (B) x/sr (C) sr/x (D) sx/r (E) rx/s For a review of everything you need to know about similar geometric figures for the GMAT, as well as a complete solution to this question, see this blog:

http://magoosh.com/gmat/2013/gmat-math-similar-shapes/
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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink ]
09 Mar 2013, 13:36

Similar Triangle

Y/x = s/r

Hence Y = sx/r

Choice D

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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink ]
27 Oct 2013, 20:09

I understood that the triangles were similar but wasn't sure how that was going to help me get the answer.

I plugged some numbers and derived the answer for y in my hypothetical situation

I said

r= 5 ,s = 10, x= 10 . I figured the ratio of the lengths of the two sides would hold since they are similar triangle.

So my equation looked like this.

\frac{r}{s} =

\frac{5}{10} and

\frac{x}{y}=\frac{10}{y} With this simple equation y=20. So i backed solved to get to the equation.

\frac{r}{s} =

\frac{1}{2} and

y=2*x or

20=2*10 . Therefore to get 20 I had to take the reciprocal of

\frac{r}{s} and multiply that by x.

So my answer would be

\frac{sx}{r} or choice D.

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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N,
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27 Oct 2013, 20:09

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