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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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09 Mar 2013, 14:36

Similar Triangle Y/x = s/r Hence Y = sx/r Choice D _________________

Regards SD ----------------------------- Press Kudos if you like my post. Debrief 610-540-580-710(Long Journey): http://gmatclub.com/forum/from-600-540-580-710-finally-achieved-in-4th-attempt-142456.html

Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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27 Oct 2013, 21:09

I understood that the triangles were similar but wasn't sure how that was going to help me get the answer.

I plugged some numbers and derived the answer for y in my hypothetical situation

I said \(r= 5 ,s = 10, x= 10\). I figured the ratio of the lengths of the two sides would hold since they are similar triangle.

So my equation looked like this. \(\frac{r}{s}\)= \(\frac{5}{10}\) and \(\frac{x}{y}=\frac{10}{y}\)

With this simple equation y=20. So i backed solved to get to the equation.

\(\frac{r}{s}\)=\(\frac{1}{2}\)and \(y=2*x\) or \(20=2*10\). Therefore to get 20 I had to take the reciprocal of \(\frac{r}{s}\) and multiply that by x.

So my answer would be\(\frac{sx}{r}\) or choice D.

Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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27 Mar 2015, 11:16

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